SOMEONE PLEEEAASSEE HELP ME T.T . This is due today! 40 points!!! I need to know how to find the x-axis.

Will two separate 50db sounds together constitute a 100db sound explain mathematical

vfiekz [6]

Putting together two distinct 50 dB sound, do not create a 100 dB sound. Since decibels are logarithm of energy, creating two sounds together only makes the energy increase but the logarithm only goes up by somehow little. So increasing the sound by 10 dB, only makes it 10000 times louder because each 10 dB increase in sound makes the sound 10 times louder.

Twice as loud is an increase of 10Log (2) = 3.01 dB. So, 53,01 dB is twice as loud as 50dB.

5 0

3 years ago

A 10 kg bear is running to the right at 10 m/s. He crashes into another 10 kg bear running to the left at -5 m/s. They collide a

faust18 [17]

Answer:

Total momentum is conserved

Explanation:

Conservation of Momentum

The momentum is a physical magnitude that measures the product of the object's velocity by its mass. The total momentum of a system is the sum of all its components' individual momentums. The two-bear system starts with a total moment of

$p=m_1v_1+m_2v_2=(10)(10)+(10)(-50)=50\ kg.m/s$

When both bears stick together, the total mass is 20 kg, and the new momentum is

$p'=(20)(2.5)=50 \ kg.m/s$

We have assumed both bears move to the right after the collision. In this situation, the total momentum is conserved

7 0

3 years ago

A 1.50 µF capacitor and a 3.50 µF capacitor are connected in series across a 2.50 V battery. How much charge (in µC) is stored o

Nataly_w [17]

Explanation:

The given data is as follows.

$C_{1} = 1.50 \times 10^{-6} F$

$C_{1} = 3.50 \times 10^{-6} F$

Voltage = 2.50 V

Hence, calculate the equivalence capacitor as follows.

$\frac{1}{C} = \frac{1}{C_{1}} + \frac{1}{C_{2}}$

$\frac{1}{C} = \frac{1}{1.50 \times 10^{-6} F} + \frac{1}{3.50 \times 10^{-6} F}$

= $0.945 \times 10^{-6} F$

C = $1.06 \times 10^{-6} F$

Now, we will calculate the charge across each capacitance as follows.

Q = CV

= $1.06 \times 10^{-6} F \times 2.50 V$

= $2.65 \times 10^{-6} C$

= $2.65 \mu C$

Thus, we can conclude that $2.65 \mu C$ is the charge stored on each given capacitor.

5 0

3 years ago

as an aid in understanding this problem. The drawing shows a positively charged particle entering a 0.61-T magnetic field. The p

miv72 [106K]

Answer:

E = 420.9 N/C

Explanation:

According to the given condition:

$Net\ Force = 2(Magnetic\ Force)\\Electric\ Force - Magnetic\ Force = 2(Magnetic\ Force)\\Electric\ Force = 3(Magnetic\ Force)\\qE = 3qvBSin\theta\\E = 3vBSin\theta$

where,

E = Magnitude of Electric Field = ?

v = speed of charge = 230 m/s

B = Magnitude of Magnetic Field = 0.61 T

θ = Angle between speed and magnetic field = 90°

Therefore,

$E = (3)(230\ m/s)(0.61\ T)Sin90^o$

E = 420.9 N/C

3 0

3 years ago

Mike has swelling in his nasal and sinus tissues. What type of medication will help him with this condition?

krok68 [10]

Aromatherapy based treatment can offer impermanent help when nasal and sinus tissue drainage blockage and pressure for Mike.

Explanation:

Nasal and sinus tissues provide stuffy nose and pain or pressure in several areas around the face or teeth. There's normally a nasal release that might be yellow, green, or clear. You may likewise have exhaustion, the issue with a feeling of smell or taste, hack, sore throat, terrible breath, migraine, torment when you twist forward, and fever.

For this issue, Mike can utilize Aromatherapy based treatment that can offer some quick help with discomfort on the blocked nose and migraine. During this stage, mike ought to breathe in some restorative or common smell to control his sufferings. Fragrance, for example, Peppermint, Eucalyptus, Tea tree, Oregano, Clary wise, Lavender, Rosemary, and so forth are a great idea to breathe in.

6 0

3 years ago