Answer:
As a science fair project, you want to launch an 950g model rocket straight up and hit a horizontally moving target as it passes 33.0m above the launch point. The rocket engine provides a constant thrust of 20.0N . The target is approaching at a speed of 18.0m/s . At what horizontal distance between the target and the rocket should you launch?
= 43.56m
Explanation:
acceleration =
(20 - (0.95 * 9.8) )/ (0.95)
= 10.68 / 0.95
= 11.24 m/s²
we use
s = ut + (1/2) at²
Given that
s= 40
u =0
s = 0 * t + (1/2) (11.24)t²
t = √(66/1.24)
t = √5.87
t = 2.42sec
hence
Horizontal distance = 18 * 2.42
= 43.56m
Increasing ; moving away
This indicates the light's wavelengths are (increasing) and the star or galaxy is (moving away.)
D. Yield signs is the answer
Answer:
hope u can understand the method
Answer:
(b) a hydrogen atom
Explanation:
Wavelength is inversely proportional to energy. So we have to find the system for which the second photon has smaller energy than the first one.
For the harmonic oscillator, the energy level spacing remains the same as the quantum number increases.
For the hydrogen atom, the energy level spacing decreases as the quantum number increases.
For the particle in a box, the energy level spacing increases as the quantum number increases.
