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3 years ago

PLEASE HELP ME I NEED HELP DESPERATELY!!!!

Mathematics

1 answer:

IceJOKER [234]3 years ago

5 0

I hope this helps, pls tell me if my way of answering is wrong
Answer:
2x-3y=4
x-2y=4

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The first term of an arithmetic sequence is 3. The common difference of the sequence is 1.5 times the first term. Write the next

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Answer:

Step-by-step explanation:

Tn = a + (n-1)d

a = 3 and d = 1.5×3 = 4.5

T2 = a + d = 3 + 4.5 = 7.5

T3 = a + 2d = 3 + 2(4.5) = 12

T4 = a + 3d = 3 + 3(4.5) = 16.5

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3 years ago

Find an explicit formula for the arithmetic sequence -31,-27,-23,-19,...

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First term (a) = -31

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3 years ago

a car dealership offers two choices of discount on a card with the sticker price of 25,000 toys eight 4000 rebate

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The answer to this question is 6.25
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3 years ago

Each time a shopper purchases a tube of toothpaste, he chooses either brand A or brand B. Suppose that for each purchase after t

konstantin123 [22]

Answer:

$\dfrac{1}{27}$

Step-by-step explanation:

Let the required probability be denoted by P(1A 2A 3B 4B).

This means a shopper chooses brand A first. Then by choosing brand A as the second purchase, the same brand is used. The third purchase is brand B; hence he switches brand. The fourth purchase is also brand B, maintaining the same brand as the third.

On the first purchase, the probabilities of A and B are both equal. Hence, each probability = 1/2

$P(\text{1A 2A 3B 4B}) = P(\text{A}) \times P(\text{same brand}) \times P(\text{different brand}) \times P(\text{same brand})$

$P(\text{1A 2A 3B 4B}) = \dfrac{1}{2}\times\dfrac{1}{3}\times\dfrac{2}{3}\times\dfrac{1}{3} = \dfrac{1}{27}$

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4 years ago