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2 years ago

Kurt can make $62 in 5 hours. How much does he make per hour?

Mathematics

1 answer:

swat322 years ago

8 0

Answer:

$12.40

Step-by-step explanation:

62/5=12 2/5

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A square has a diagonal of 44in. I want to frame the picture, how many inches of frame do I need

dimaraw [331]

The square has a 44-inch diagonal.

The pythagorean equation must be used to obtain the hand.

Diagonal (d) ^ 2 = side^2 + side ^ 2

Diagonal (d) ^ 2 = 2side (s)^2

d^2 = 2s^2

44^2 = 2s^2

1936 = 2s^2

2s^2 = 1936

s^2 = 968

s = 31.11 inches

The length of the side is around 31 inches

Perimeter = 4*s

Perimeter = 4 * 31

Perimeter = 124 inches

As a result, you will need a total of 124 inches to frame the rectangle.

Hope this helps you!!

8 0

3 years ago

PLZ HELP!This is my only question left!!! plzzzzz

hram777 [196]

Answer:

12.84 degrees

Step-by-step explanation:

sin(x)=2/9

5 0

3 years ago

A scientist claims that 7% 7 % of viruses are airborne. If the scientist is accurate, what is the probability that the proportio

Reptile [31]

Answer:

The probability is $P(|p-\^{p}| > 0.03) = 0.0040$

Step-by-step explanation:

From the question we are told that

The population proportion is $p = 0.07$

The mean of the sampling distribution is $\mu_p = 0.07$

The sample size is n = 600

Generally the standard deviation is mathematically represented as

$\sigma_p = \sqrt{\frac{p (1 -p)}{n} }$

=> $\sigma_p = \sqrt{\frac{0.07(1 -0.07)}{600} }$

=> $\sigma_p = 0.010416$

Generally the probability that the proportion of airborne viruses in a sample of 600 viruses would differ from the population proportion by greater than 3% is mathematically represented as

$P(|p-\^{p}| > 0.03) = 1 - P(|p -\^{p}| \le 0.03)$

=> $P(|p-\^{p}| > 0.03) = 1 - P(-0.03 \le p -\^{p} \le 0.03 )$

Now add p to both side of the inequality

=> $P(|p-\^{p}| > 0.03) = 1 - P( 0.07-0.03 \le \^{p} \le 0.03+ 0.07 )$

=> $P(|p-\^{p}| > 0.03) = 1 - P(0.04 \le \^{p} \le 0.10 )$

Now converting the probabilities to their respective standardized score

=> $P(|p-\^{p}| > 0.03) = 1 - P(\frac{0.04 - 0.07}{0.010416} \le Z \le \frac{0.10 -0.07}{0.010416} )$

=> $P(|p-\^{p}| > 0.03) = 1 - P(-2.88 \le Z \le 2.88 )$

=> $P(|p-\^{p}| > 0.03) = 1 - [P(Z \le 2.88) - P(Z \le -2.88)]$

From the z-table

$P(Z \le 2.88) = 0.9980$

and

$P(Z \le -2.88) = 0.0020$

$P(|p-\^{p}| > 0.03) = 1 - [0.9980 - 0.0020]$

=> $P(|p-\^{p}| > 0.03) = 0.0040$

7 0

3 years ago

3x+2(4x+2)≤2(6x+1)<br> Please help its algebra

Fiesta28 [93]

Answer:

1≤x

Step-by-step explanation:

3x+2(4x+2)≤2(6x+1)

3x+8x+4≤12x+2

4-2≤12x-3x-8x

2≤2x

1≤x

4 0

3 years ago

Mrs Foley picked 27 flowers from her garden so her 3 children could each give a bouquet to their teachers. If each bouquet had t

nignag [31]

Answer:

Step-by-step explanation:

27/3

4 0

3 years ago