A gas occupies 1.00 L at standard temperature. What is the volume at 606 K?

1 answer:

3 0

Answer:

the volume at 606k is 2.22....the third one

Step-by-step explanation:

v1=1.00 t1=273 v2=? t2=606

v1/t1=v2/t2

1.00/273=v2/606

1.00×606=273v2

606=273v2

606/273=v2

2.21 L=v2

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