Answer:
the chemical element of atomic number 16, a yellow combustible nonmetal.
Explanation:
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Answer is: 8568.71 of baking soda.
Balanced chemical reaction: H₂SO₄ + 2NaHCO₃ → Na₂SO₄ + 2CO₂ + 2H₂O.
V(H₂SO₄) = 17 L; volume of the sulfuric acid.
c(H₂SO₄) = 3.0 M, molarity of sulfuric acid.
n(H₂SO₄) = V(H₂SO₄) · c(H₂SO₄).
n(H₂SO₄) = 17 L · 3 mol/L.
n(H₂SO₄) = 51 mol; amount of sulfuric acid.
From balanced chemical reaction: n(H₂SO₄) : n(NaHCO₃) = 1 :2.
n(NaHCO₃) = 2 · 51 mol.
n(NaHCO₃) = 102 mol, amount of baking soda.
m(NaHCO₃) = n(NaHCO₃) · M(NaHCO₃).
m(NaHCO₃) = 102 mol · 84.007 g/mol.
m(NaHCO₃) = 8568.714 g; mass of baking soda.
Answer:
39.0983.
Explanation:
you are converting between grams Potassium and mole. You can view more details on each measurement unit: molecular weight of Potassium or mol The molecular formula for Potassium is K. The SI base unit for amount of substance is the mole.
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The amount of solute that will crystallize out of the supersaturated solution when it returns to being a saturated solution at 0°C is 46 g
<h3>Saturated and Supersaturated Solution</h3>
- A saturated solution is a solution that contains as much solute as it can dissolve at that temperature in the presence of undissolved solute particles
- A supersaturated solution is a solution which contains more solute than it can normally hold at that temperature.
A supersaturated solution is unstable and the excess solute will separate out of the solution if disturbed slightly or a tiny solute crystal is added to it.
<h3>Solubility curves</h3>
- A solubility curve is a graph or curve of solubility of a substance against temperature.
It is a curve that shows the effect of temperature on solubility of of a substance.
From the solubility data provided, the amount of solute that will crystallize out of solution can be determined:
- Solubility of AgNO3 at 60°C = 106 g/100g H2O
- Solubility of AgNO3 at 0°C is 60 g/100 g H20
When the solution was cooled to form a supersaturated solution, the solution contains 106g of AgNO3
When the solution returns to being a saturated solution at 0°C:
Amount of solute that crystallizes out = 106g - 60 g
Amount of solute that crystallizes out = 46 g
Therefore, the amount of solute that will crystallize out of the supersaturated solution when it returns to being a saturated solution at 0°C is 46 g
Learn more about solubility, saturated solutions and supersaturated solutions at: brainly.com/question/9712781
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