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Tcecarenko [31]
3 years ago
12

How would you write out the full chemical reaction for Copper (2) Iodide+Silver ----> Silver Iodide+Copper

Chemistry
1 answer:
DENIUS [597]3 years ago
3 0
CI2Au it is right your welcome
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What are four factors that affect the rate of a chemical reaction
Alexeev081 [22]
Reactant concentration, the physical state of the reactants, and surface area, temperature, and the presence of a catalyst are the four main factors that affect reaction rate.
4 0
4 years ago
Determine the volume (in liters) of a 87.8-9 sample of OF2 gas at 307 torr and 264°C.
expeople1 [14]

Answer:

V = 177.4 L.

Explanation:

Hello there!

In this case, since this gas can be assumed as ideal due to the given data, we can use the following equation:

PV=nRT\\\\PV=\frac{m}{MM}RT

Thus, by solving for volume we obtain:

V=\frac{mRT}{MM*P}

So we can plug in the temperature in Kelvins (537 K), the pressure in atmospheres (0.404 atm) and the molar mass (54 g/mol) to obtain:

V=\frac{87.8g*0.08206\frac{atm*L}{mol*K}*537K}{54g/mol*0.404atm}\\\\V=177.4L

Best regards!

6 0
3 years ago
Which best represents a reaction mechanism?
PIT_PIT [208]
A + B = Products
This is the correct mechanism.
6 0
3 years ago
You have a solution with 2.52 moles of isopropanol (C3H8O). The solution weighs 521 grams. What is the percent composition of is
Kamila [148]

Answer:

The Percent composition of isopropanol in the mixture is 29.07 %

Explanation:

Step 1: Data given

Number of moles isopropanol (C3H8O) = 2.52 moles

Mass of the solution = 521 grams

Molar mass of isopropanol (C3H8O) = 60.1 g/mol

Step 2: Calculate mass of isopropanol

Mass isopropanol = moles isopropanol * molar mass isopropanol

Mass isopropanol = 2.52 moles * 60.1 g/mol

Mass isopropanol = 151.45 grams

Step 3: Calculate the percent composition of isopropanol in the mixture

Percent composition of isopropanol = (mass isopropanol / total mass of mixture) * 100 %

Percent composition of isopropanol = (151.45 grams / 521 grams ) * 100 %

Percent composition of isopropanol = 29.07 %

The Percent composition of isopropanol in the mixture is 29.07 %

8 0
4 years ago
Read 2 more answers
Discuss the reaction of sodium iodide with sodium hypochlorite solution
Angelina_Jolie [31]

The reaction of sodium hypochlorite (NaOCl, bleach) with iodide ion (sodium iodide) leads to the formation of electrophile. The I⁺ ion formed in this reaction is a strong electrophile that reacts quickly in an electrophilic aromatic substitution reaction.

NaOCl + NaI = I⁺  

4 0
4 years ago
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