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galben [10]
3 years ago
14

Another saturated solution containing 106gAl * (NO3)3 / 100 g H2O O at 60^C (=106g) is very carefully cooled down in an ice bath

(0 ^ 5 * C) (=60g) to produce an unstable supersaturated solution. A single tiny "seed crystal" is then added to induce crystallization. How many grams of Al(NO 3 ) 3 will crystallize out of the solution when it returns to being a saturated solution?

Chemistry
1 answer:
Thepotemich [5.8K]3 years ago
7 0

The amount of solute that will crystallize out of the supersaturated solution when it returns to being a saturated solution at 0°C is 46 g

<h3>Saturated and Supersaturated Solution</h3>
  • A saturated solution is a solution that contains as much solute as it can dissolve at that temperature in the presence of undissolved solute particles
  • A supersaturated solution is a solution which contains more solute than it can normally hold at that temperature.

A supersaturated solution is unstable and the excess solute will separate out of the solution if disturbed slightly or a tiny solute crystal is added to it.

<h3>Solubility curves</h3>
  • A solubility curve is a graph or curve of solubility of a substance against temperature.

It is a curve that shows the effect of temperature on solubility of of a substance.

From the solubility data provided, the amount of solute that will crystallize out of solution can be determined:

  • Solubility of AgNO3 at 60°C = 106 g/100g H2O
  • Solubility of AgNO3 at 0°C is 60 g/100 g H20

When the solution was cooled to form a supersaturated solution, the solution contains 106g of AgNO3

When the solution returns to being a saturated solution at 0°C:

Amount of solute that crystallizes out = 106g - 60 g

Amount of solute that crystallizes out = 46 g

Therefore, the amount of solute that will crystallize out of the supersaturated solution when it returns to being a saturated solution at 0°C is 46 g

Learn more about solubility, saturated solutions and supersaturated solutions at: brainly.com/question/9712781

brainly.com/question/24564260

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MakcuM [25]

Answer:

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8 0
3 years ago
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If a gas is initially at a pressure of 9 atm, a volume of 21 liters, and a temperature of 253 K, and then the pressure is raised
alex41 [277]

Answer:

15.04 mL

Explanation:

Using Ideal gas equation for same mole of gas as

\frac {{P_1}\times {V_1}}{T_1}=\frac {{P_2}\times {V_2}}{T_2}

Given ,  

V₁ = 21 L

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P₁ = 9 atm

P₂ = 15 atm

T₁ = 253 K

T₂ = 302 K

Using above equation as:

\frac {{P_1}\times {V_1}}{T_1}=\frac {{P_2}\times {V_2}}{T_2}

\frac {{9}\times {21}}{253}=\frac {{15}\times {V_2}}{302}

Solving for V₂ , we get:

<u>V₂ = 15.04 mL</u>

3 0
3 years ago
Answer all parts of the following questions on Particle Stoichiometry.
Sever21 [200]
1. Translate, predict the products, and balance the equation above. 

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2. How many particles of lithium are needed to produce 125 g of copper? 

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3. How many grams of lithium nitrate are produced from 4.83E24 particles of copper (II) nitrate?

4.83E24 particles of copper (II) nitrate ( 1 mol / 6.022x10^23 particles ) (1 mol Li(NO3)2 / 1 mol Cu(NO3)2 ) ( 130.95 g / 1 mol ) = <span>1043.77 grams Li(NO3)2</span>
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Propane burns in air to form water vapor and another gas. What is the volume of the water vapor at 500°C and 1 atm?​
kakasveta [241]

Answer:

253.85 L

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

C₃H₈ + 5O₂ —> 3CO₂ + 4H₂O

From the balanced equation above, 4 moles of water vapor were produced.

Finally, we shall determine the volume of the water vapor produced as follow:

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Thus, the volume of water vapor obtained is 253.85 L

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