1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
zheka24 [161]
3 years ago
13

The total amount of energy before and after a chemical reaction is the same. Therefore, energy is _____.

Chemistry
2 answers:
BabaBlast [244]3 years ago
8 0

Answer:

Option (a) is the correct answer.

Explanation:

The law of conservation of energy states that energy can neither be created nor it can be destroyed. It can only be transformed from one form to another.

Therefore, the total amount of energy before and after a chemical reaction is the same. Thus, energy is conserved.

Therefore, we can conclude that option (a) is the correct answer.

allsm [11]3 years ago
7 0

Answer:

conserved

Explanation:

law of conservation of energy says that energy can neither be created or destroyed

You might be interested in
How to find the relationship between slope and speed
devlian [24]
You can study article about slope and speed 
3 0
3 years ago
If copper (II) sulfate solution and an iron nail are in contact, a replacement reaction occurs. What would the products of the r
KonstantinChe [14]
The  product  of   replacement  reaction  of  2Fe  + 3  CUSO4  yield  2Fe(SO4)3  +  3  Cu

during   replacement  reaction  involve   replacement  of  less   reactive  element   in the  reactivity  series  from  its  compound.  Fe  is  more  reactive  in  the reactivity  series   than  cu  therefore  it  Fe replaces   cu  from    CUSO4
6 0
4 years ago
Read 2 more answers
What is stoichiometry used for
Dennis_Churaev [7]

Answer:

Stoichiometry measures these quantitative relationships, and is used to determine the amount of products and reactants that are produced or needed in a given reaction.

3 0
4 years ago
Read 2 more answers
The volume occupied by 1.5 mole of gas at 35°C and 2.0 atmosphere of pressure is blank liters
Aneli [31]

Answer: 18.97 L

Explanation:

This can be solved by the Ideal Gas equation:

P.V=n.R.T  

Where:  

P=2 atm is the pressure of the gas  

V is the volume of the gas  

n=1.5 mole the number of moles of gas  

R=0.0821\frac{L.atm}{mol.K} is the gas constant  

T=35\°C+273.15=308.15 K is the absolute temperature of the gas in Kelvin

Finding V:

V=\frac{nRT}{P}

V=\frac{(1.5 mole)(0.0821\frac{L.atm}{mol.K})(308.15 K)}{2 atm}

V=18.97 L

Therefore:

The volume occupied by 1.5 mole of gas at 35°C and 2.0 atmosphere of pressure is <u>18.97</u> liters

7 0
3 years ago
The Big Bang really happened. But within milliseconds, the universe expanded or inflated so rapidly that the universe is flat an
telo118 [61]

What are we trying to answer?

8 0
3 years ago
Other questions:
  • 2. In the reaction H2(g) + b(0) + 2HI(), there are equilibrium partial pressures of PH, = 13.0 MPa, P = 11.7 MPa and Phi = 66.6
    13·1 answer
  • What is the total number of oxygen atoms on the right-hand side of this chemical equation?
    11·1 answer
  • Which statement about the discovery of electrons is true?
    13·1 answer
  • When a gamma ray is emitted from the nucleus of an atom: it reduces the overall energy of the nucleus it increases the overall e
    14·1 answer
  • Sue found a ring and wanted to know
    8·1 answer
  • It's sunny in New York But it is cooL During the first part of the week, we might find this lizard basking in the sun
    10·1 answer
  • Ethyl ethanoate undergoes following reaction [on the picture]
    10·1 answer
  • What is the formula for the stable binary ionic compound formed between Barium and Oxygen?
    12·1 answer
  • Isotopes are different types of atoms of the same element, but with a different number of __________ ?
    5·2 answers
  • Exactly 17.0 mL of a H2SO4 solution was required to neutralize 45.0 mL of 0.235 M NaOH. What was the concentration of the H2SO4
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!