Answer:
That pencil doesn't adjust to that ipad because those two aren't compatible
Explanation:
Answer:
Explanation:
#include <iostream>
using namespace std;
int costdays(int);
int costhrs(int,int);
int main()
{
int dd,hh,mm,tmph,tmpd,tmpm=0;
int pcost,mcost=0;
cout<<"Enter Parking time" << endl;
cout<<"Hours: ";
cin>>hh;
cout<<"Minutes: ";
cin>>mm;
if (mm>60)
{
tmph=mm/60;
hh+=tmph;
mm-=(tmph*60);
}
if (hh>24)
{
tmpd=hh/24;
dd+=tmpd;
hh-=(tmpd*24);
}
if ((hh>4)&&(mm>0))
{
pcost+=costdays(1);
}
else
{
mcost=costhrs(hh,mm);
}
cout<<"Total time: ";
if (dd>0)
{
cout<<dd<<"days ";
pcost+=costdays(dd);
}
pcost+=mcost;
cout<<hh<<"h "<<mm<<"mins"<<endl;
cout<<"Total Cost :"<<pcost<<"Won";
return 0;
}
int costdays(int dd)
{
return(dd*25000);
}
int costhrs(int hh,int mm)
{
int tmpm, tmp=0;
tmp=(hh*6)*1000;
tmp+=(mm/10)*1000;
tmpm=mm-((mm/10)*10);
if (tmpm>0)
{
tmp+=1000;
}
return(tmp);
}
Answer:
error: incompatible types
Explanation:
Given
The attached code
Required
The output
Variable "a" is declared as float
While p is declared as a pointer to an integer variable
An error of incompatible types will be returned on line 3, <em>int *p = a;</em>
Because the variables are not the same.
To assign a to p*, we have to use type casting.
Hence, (b) is correct
<u>Normally windows end user can login 3 ways as follow:</u>
1. End user can Login as local account where user has not connected or even connected to local Area network LAN.
2. Next user can login into cloud accounts nothing but hot mail accounts
3. Login to windows domain controller where end user should connect to LAN.
Purpose of installation of Windows domain controller with Active Directory is to keep trace and keep log history activities.
Due to windows domain controller with Active Directory end user desktop or laptop has control on software access also.
Every time when end user login on windows domain controller a small modified is executed whenever is required. It is not going effort the workstation performances.
Note: - Domain severs should be POWER on first.
