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4 years ago

PLEASE HELP ASAP!!

1 answer:

3 0

Velocity is displacement over time, so do 60/8 to get 7.5 yards per second, and remember to add the direction the ball is traveling in.

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A proton is projected in the positive x direction into a region of a uniform electric field E S 5 126.00 3 105 2 i^ N/C at t 5 0

Dafna11 [192]

Answer:

(a). The magnitude of the acceleration of the proton is $5.74\times10^{13}\ m/s^2$

(b). The initial peed of the protion is $2.83\times10^{6}\ m/s$

(c). The time is $0.493\times10^{-7}\ sec$ .

Explanation:

Given that,

Electric field $E=-6.00\times10^{5}i\ N/C$

Time = 5.0 sec

Distance 7.00 cm

(a). We need to calculate the acceleration

Using formula of force

$F=F_{e}$

$ma=qE$

$a=\dfrac{Eq}{m}$

Where, E = electric field

m = mass of proton

q = charge of proton

Put the value into the formula

$a=\dfrac{-6.00\times10^{5}\times1.6\times10^{-19}}{1.67\times10^{-27}}$

$a=-5.74\times10^{13}\ m/s62$

The magnitude of the acceleration of the proton is $5.74\times10^{13}\ m/s^2$

(b). We need to calculate the initial peed

Using equation of motion

$v^2-u^2=2as$

Where, s = distance

Put the value into the formula

$0-u^2=2\times(-5.74\times10^{13})\times7.00\times10^{-2}$

$u=\sqrt{2\times5.74\times10^{13}\times7.00\times10^{-2}}$

$u=2834783.94$

$u=2.83\times10^{6}\ m/s$

The initial peed of the protion is $2.83\times10^{6}\ m/s$

(c). We need to calculate the time interval over which the proton comes to rest

Using formula

$t=\dfrac{u}{a}$

Where, u = initial velocity

a = acceleration

Put the value into the formula

$t=\dfrac{2.83\times10^{6}}{5.74\times10^{13}}$

$t=0.493\times10^{-7}\ sec$

Hence, (a). The magnitude of the acceleration of the proton is $5.74\times10^{13}\ m/s^2$

(b). The initial peed of the protion is $2.83\times10^{6}\ m/s$

(c). The time is $0.493\times10^{-7}\ sec$ .

5 0

3 years ago

Water drips from a faucet at the rate of 150 drops in 120 seconds. What is the period?

user100 [1]

Answer:

.80

Explanation:

7 0

3 years ago

What is the wavelenght and the frequencen of walkie-talkie?

GuDViN [60]

Nowadays, most of the walkie talkies ... and all R/C models ... operate in the "Family Radio Service" (FRS) band. That's 46-49 MHz. The wavelength is 6.12-6.52 meters.

8 0

3 years ago

Match the cloud type with its description. 1. cumulus

Bond [772]

Answers

1. cumulus ⇒ b. look like pieces of cotton in the sky

2. altostratus ⇒ c. resembles an overcast sky; layers of gray or white clouds

3. cirrus ⇒ a. look like wispy feathers high in the sky

4. nimbostratus ⇒ E.dark, thick-layered clouds; rain's coming

5. fog ⇒ d. clouds nearest Earth's surface

7 0

3 years ago

Read 2 more answers

An infinite sheet of charge is located in the y-z plane at x = 0 and has uniform charge denisity σ1 = 0.37 μC/m2. Another infini

Firlakuza [10]

Answer:

The x-component of the electric field at point P -- 31,638.41

Explanation:

Given data:

charge density $\sigma_1 =0.37 \muC/m^2$

Another charge density $\sigma_2 = -0.19 \mu C/m^2$

Electric field due to infinite sheet of charge is given as E

$E = \frac{\sigma}{2\epsilon}$

$E_{NET} = E_1 + E_2$

$= \frac{\sigma_1}{2\epsilon} + \frac{\sigma_2}{2\epsilon}$

$= \frac{0.37\times 10^{-6}}{2\times 8.85\times 10^{-12}} + \frac{0.19\times 10^{-6}}{2\times 8.85\times 10^{-12}}$

= 31,638.41

7 0

3 years ago