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snow_tiger [21]
2 years ago
10

The spaceship Intergalactica lands on the surface of the uninhabited Pink Planet, which orbits a rather average star in the dist

ant Garbanzo Galaxy. A scouting party sets out to explore. The party's leader–a physicist, naturally–immediately makes a determination of the acceleration due to gravity on the Pink Planet's surface by means of a simple pendulum of length 1.081.08 m. She sets the pendulum swinging, and her collaborators carefully count 101101 complete cycles of oscillation during 2.00×1022.00×102 s. What is the result? acceleration due to gravity:acceleration due to gravity: m/s2
Physics
1 answer:
Sidana [21]2 years ago
7 0

Complete Question

The spaceship Intergalactica lands on the surface of the uninhabited Pink Planet, which orbits a rather average star in the distant Garbanzo Galaxy. A scouting party sets out to explore. The party's leader–a physicist, naturally–immediately makes a determination of the acceleration due to gravity on the Pink Planet's surface by means of a simple pendulum of length 1.08m. She sets the pendulum swinging, and her collaborators carefully count 101 complete cycles of oscillation during 2.00×102 s. What is the result? acceleration due to gravity:acceleration due to gravity: m/s2

Answer:

The acceleration due to gravity is  g = 167.2 \ m/s^2  

Explanation:

From the question we are told that

     The length of the simple pendulum is L = 1.081.08 \ m

      The number of cycles is  N =  101

       The time take is  t =  2.00 *10^{2 \ }s

Generally the period of this oscillation is mathematically evaluated as

         T = \frac{N}{t }

substituting values

         T = \frac{101}{2.0*10^2 }

        T = 0.505 \  s

The period of this oscillation is mathematically represented  as

               T = 2 \pi \sqrt{\frac{l}{g} }

making g the subject of the formula we have

              g = \frac{L}{[\frac{T}{2 \pi } ]^2 }

              g = \frac{4 \pi ^2 L }{T^2 }

Substituting values

               g = \frac{4 * 3.142 ^2  * 1.08 }{505.505^2 }

               g = \frac{4 * 3.142 ^2  * 1.08 }{0.505^2 }  

              g = 167.2 \ m/s^2  

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Ek=kinetic energy  (J)
m=mass of object (Kg)
v=speed of object  (m/s)

We have the following formula:

Ek=(1/2)mv²   ⇒ m=2(Ek)/v²

In this case:
m= mass of the child + mass of the bike
m=30 kg + m₁       (m₁=mass of the bike).

We would have to modify our formula like this:

m=2(Ek)/v²
m=30 kg + m₁


30 kg +m₁=2(Ek)/v²
m₁=2(Ek)/v²-30 kg

We have the following data:

v=0.6 m/s
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m=30 Kg + m₁

Therefore:

m₁=2(Ek)/v²  - 30 kg
m₁=2(12.4 J)/(0.6 m/s)²  - 30 kg
m₁=24.8 J/(0.36 m²/s²)  -30 kg
m₁=68.89 Kg - 30 kg
m₁=38.89 Kg

Answer: the mass of the bike is 38.89 Kg. 



8 0
3 years ago
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Hey guys.. what’s 1,893,9379 x 0
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