Ek=kinetic energy (J)
m=mass of object (Kg)
v=speed of object (m/s)
We have the following formula:
Ek=(1/2)mv² ⇒ m=2(Ek)/v²
In this case:
m= mass of the child + mass of the bike
m=30 kg + m₁ (m₁=mass of the bike).
We would have to modify our formula like this:
m=2(Ek)/v²
m=30 kg + m₁
30 kg +m₁=2(Ek)/v²
m₁=2(Ek)/v²-30 kg
We have the following data:
v=0.6 m/s
Ek=12.4J
m=30 Kg + m₁
Therefore:
m₁=2(Ek)/v² - 30 kg
m₁=2(12.4 J)/(0.6 m/s)² - 30 kg
m₁=24.8 J/(0.36 m²/s²) -30 kg
m₁=68.89 Kg - 30 kg
m₁=38.89 Kg
Answer: the mass of the bike is 38.89 Kg.
<h2>Hello there, to answer your question...</h2><h2 /><h2>1,893,9379 x 0 = 0</h2><h2 /><h2>Anything times zero is always 0</h2><h2 /><h2>For example</h2><h2>1x0=0</h2><h2>4x0=0</h2><h2>12x0=0</h2><h2>48x0=0</h2><h3>I hope this helps :)</h3>
Answer:
this is just a guess bc i only looked at it for 5 seconds but i think 150 m/s
Answer:
induced current
Explanation:
intentionally manipulated.
Answer:
91.84 m/s²
Explanation:
velocity, v = 600 m/s
acceleration, a = 4 g = 4 x 9.8 = 39.2 m/s^2
Let the radius of the loop is r.
he experiences a centripetal force.
centripetal acceleration,
a = v² / r
39.2 x r = 600 x 600
r = 3600 / 39.2
r = 91.84 m/s²
Thus, the radius of the loop is 91.84 m/s².