Question

A spherical aluminum ball of mass 1.26 kg contains an empty spherical cavity that is concentric with the ball. The ball barely floats in water. Calculate (a) the outer radius of the ball and

Answer 1

The outer radius of the ball = 6.70cm.

What is Buoyant Force?

The upward force applied to an object that is fully or partially submerged in a fluid is known as the buoyant force.

Given: Mass of aluminum ball = $m_{b}=1.26kg$

To find: The outer radius of the ball.

Finding:

As Buoyant Force = $F_{b}=e\times(g)\times\frac{4}{3}\pi(r)^{3}$,

The weight of the ball should be equal to the buoyant force since it floats on the water.

That is,

=> $1.26=e_{water}(g)(\frac{4}{3}\pi(r_{outer})^{3})$

=> $r_{outer}=(\frac{3\times1.26}{g\times(e_{water})4\times3.14})^\frac{1}{3}$

Upon substitution of values of $e_{water}$ and g, we get: $r_{outer}=6.70cm$

Hence, the outer radius of the ball = 6.70cm

To learn more about Buoyant Force, refer to the link: brainly.com/question/17009786

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