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3 years ago

Which expression represents 2 more than the product 5 and 4.

Mathematics

2 answers:

Vikki [24]3 years ago

6 0

B
the product is (5x4)
and adding 2 is two more than the product

Andrej [43]3 years ago

4 0

Answer:

i think it's B. (5 x 4) + 2

Step-by-step explanation:

pls give brainly crown

and if i'm wrong i'm sooooo sorry

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One model for the spread of a rumor is that the rate of spread is proportional to the product of the fraction y of the populatio

kenny6666 [7]

Answer:

Therefore , $y= \frac{Ae^{kt}}{1+Ae^{kt} }$

Step-by-step explanation:

The fraction of population who have heard rumor = y

The fraction of population who haven't heard rumor = 1-y

The rate of of spread (y'(t)) is proportional to the product of the fraction of population who have heard rumor the fraction of population who have heard rumor.

Therefore

y'(t) ∝ y (1-y)

⇒ y'(t) =k y (1-y) [ k = constant of proportional]

$\Rightarrow \frac{dy}{dt}=ky(1-y)$

$\Rightarrow \frac{dy}{y(1-y)}=k \ dt$

Integrating both sides

$\Rightarrow \int\frac{dy}{y(1-y)}=\int k \ dt$

$\Rightarrow \int \frac{dy}{y}+\int\frac{dy}{1-y}=\int k \ dt$ $[\because \frac{1}{y(1-y}=\frac{1}{y}+\frac{1}{1-y} ]$

$\Rightarrow ln \ y- ln \ |1-y| = kt +c$ [ c = arbitrary constant]

$\Rightarrow ln|\frac{y}{1-y}|=kt +c$

$\Rightarrow \frac{y}{1-y}= e^{kt+c}$

$\Rightarrow \frac{y}{1-y}= Ae^{kt}$ [ Here $e^c=A$ ]

$\Rightarrow y = Ae^{kt}(1-y)$

$\Rightarrow y = Ae^{kt}-y Ae^{kt}$

$\Rightarrow y+y Ae^{kt} = Ae^{kt}$

$\Rightarrow y(1+Ae^{kt} )= Ae^{kt}$

$\Rightarrow y= \frac{Ae^{kt}}{1+Ae^{kt} }$

Therefore , $y= \frac{Ae^{kt}}{1+Ae^{kt} }$

5 0

3 years ago

How to write 92.5 as a fraction in simplest form

9966 [12]

92.5 = 185/2

_____
= 92.5*(2/2) = (92.5*2)/2 = 185/2

6 0

3 years ago

Travis wants to solve a quadratic equation. Since his equation cannot be factored, Travis has to graph the equation and approxim

SOVA2 [1]

Answer:

The correct answer is B.

Step-by-step explanation:

In order to find this, calculate out the discriminant for each of the following equations. If the discriminant is a perfect square, then it can be factored.

Discriminant = b^2 - 4ac

The only of the equations that does not yield a perfect square is B. The work for it is done below for you.

Discriminant = b^2 - 4ac

Discriminant = 7^2 - 4(2)(-5)

Discriminant = 49 + 40

Discriminant = 89

Since 89 is not a perfect square, we cannot factor this.

6 0

3 years ago

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What one transformation could be used to show that AABC ~AA"B" C" directly?

stira [4]

Answer:

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7 0

3 years ago

Approximate the value of 11−−√ to the nearest tenths place. Plot the approximation on the number line.

posledela

Step-by-step explanation:

I think your question is missed of key information, allow me to add in and hope it will fit the original one.

<em>Approximate the value of </em> $\sqrt{11}$ <em> to the nearest tenths place. Plot the approximation on the number line.</em>

(Please have a look at the attached photo)

My answer:

The value nearest tenths place of $\sqrt{11}$ is: 3.3

Hope it will find you well.

5 0

3 years ago