Question

The sum of two numbers is 18, 5 times the number subtracted from 4 over 7 of the second number is 14 find the number​

Answer 1

Answer:

First number x = -0.6

Second number y = 18.66

Step-by-step explanation:

Let the first number = x

and Second number = y

Sum of two numbers is 18. We can write it in mathematical expression as:

$x+y=18$

5 times the number subtracted from 4 over 7 of the second number is 14. We can write it in mathematical expression as:

$\frac{4}{7}y-5x=14$

So, solving the equations simultaneously we can find value of x and y

Let:

$x+y=18--eq(1)\\\frac{4}{7}y-5x=14--eq(2)$

Finding value of x from equation 1 and put it in eq(2)

$x+y=18\\x=18-y$

Put in equation 2

$\frac{4}{7}y-5(18-y)=14\\\frac{4}{7}y-90+5y=14\\\frac{4y-90*7+5y*7}{7}=14\\ \frac{4y-90*7+5y*7}{7}=14\\ \frac{4y-630+35y}{7}=14\\ \frac{39y-630}{7}=14\\39y-630=14*7\\39y-630=98\\39y=98+630\\39y=728\\y=18.66$

So, Value of y= 18.66

Now finding value of x, By putting value of y in eq(1)

$x+y=18\\18.66+x=18\\x=18-18.66\\x=-0.6$

So, First number x = -0.6

Second number y = 18.66