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3 years ago

What information do you need to write the ordered pair for a point?

Mathematics

2 answers:

noname [10]3 years ago

5 0

Answer:

You need the x- axis and the y-axis

Step-by-step explanation:

zaharov [31]3 years ago

3 0

Answer:

When you are finding an ordered pair you need the x-coordinate and the y-coordinate.

Step-by-step explanation:

The horizontal line is the x-axis and vertical is the y-axis. When you put get the coordinate you put it as (x,y).

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Economists predict that Americans will spend $1,180 on electonics in

lisov135 [29]

Money spent by Americans last year=$1,180-6.8% of $1,180
=$1099.76

8 0

2 years ago

W+1/8 =8 plzz help me i need it

Marina CMI [18]

Answer:

w = 7 7/8

Step-by-step explanation:

w + 1/8 = 8

First, subtract 1/8 from both sides of the equation

w + 1/8 = 8

- 1/8 - 1/8

w = 7 7/8

8 0

3 years ago

Read 2 more answers

Yo which set or sets does the Number 37 belong?

Tresset [83]

It is a whole number

3 0

3 years ago

Determine formula of the nth term 2, 6, 12 20 30,42

nalin [4]

Check the forward differences of the sequence.

If $\{a_n\} = \{2,6,12,20,30,42,\ldots\}$ , then let $\{b_n\}$ be the sequence of first-order differences of $\{a_n\}$ . That is, for n ≥ 1,

$b_n = a_{n+1} - a_n$

so that $\{b_n\} = \{4, 6, 8, 10, 12, \ldots\}$ .

Let $\{c_n\}$ be the sequence of differences of $\{b_n\}$ ,

$c_n = b_{n+1} - b_n$

and we see that this is a constant sequence, $\{c_n\} = \{2, 2, 2, 2, \ldots\}$ . In other words, $\{b_n\}$ is an arithmetic sequence with common difference between terms of 2. That is,

$2 = b_{n+1} - b_n \implies b_{n+1} = b_n + 2$

and we can solve for $b_n$ in terms of $b_1=4$ :

$b_{n+1} = b_n + 2$

$b_{n+1} = (b_{n-1}+2) + 2 = b_{n-1} + 2\times2$

$b_{n+1} = (b_{n-2}+2) + 2\times2 = b_{n-2} + 3\times2$

and so on down to

$b_{n+1} = b_1 + 2n \implies b_{n+1} = 2n + 4 \implies b_n = 2(n-1)+4 = 2(n + 1)$

We solve for $a_n$ in the same way.

$2(n+1) = a_{n+1} - a_n \implies a_{n+1} = a_n + 2(n + 1)$

Then

$a_{n+1} = (a_{n-1} + 2n) + 2(n+1) \\ ~~~~~~~= a_{n-1} + 2 ((n+1) + n)$

$a_{n+1} = (a_{n-2} + 2(n-1)) + 2((n+1)+n) \\ ~~~~~~~ = a_{n-2} + 2 ((n+1) + n + (n-1))$

$a_{n+1} = (a_{n-3} + 2(n-2)) + 2((n+1)+n+(n-1)) \\ ~~~~~~~= a_{n-3} + 2 ((n+1) + n + (n-1) + (n-2))$

and so on down to

$a_{n+1} = a_1 + 2 \displaystyle \sum_{k=2}^{n+1} k = 2 + 2 \times \frac{n(n+3)}2$

$\implies a_{n+1} = n^2 + 3n + 2 \implies \boxed{a_n = n^2 + n}$

6 0

2 years ago

How to write3.repeating 7 as a mixed number

ki77a [65]

Hey there! I'm happy to help!

Let's call our fraction x.

x=3.777......

We want to get rid of the repeating stuff. If we multiply our fraction by 10, we get 10x=37.7777.

We see that if we subtract x from 10x, the repeating numbers will be cancelled out. Let's do this.

10x=37.7777

x=3.77777

9x=34

We divide both sides by 9.

x=34/9=3 7/9.

Have a wonderful day! :D

6 0

3 years ago