Answer:
2 (real) solutions.
Step-by-step explanation:
A quadratic always has two solutions, whether they are real or complex.
Sometimes the solution is complex, involving complex numbers (2 complex), sometimes they are real and distinct (2 real), and sometimes they are real and coincident (still two real, but they are the same).
In the case of
x^2+3x = 3, or
x² + 3x -3 = 0
we apply the quadratic formula to get
x = (-3 +/- sqrt(3^2+4(1)(3))/2
to give the two solutions
{(sqrt(21)-3)/2, -(sqrt(21)+3)/2,}
both of which are real.
Answer:
g^2 + 4
I literally do not know how to explain it. I solved this problem with the clues like sum and squared. I looked at where these words were located.
Answer:
Assume that the formula is true for the (k+1)term
Step-by-step explanation:
I learned this in class a couple weeks ago in intermediate algebra
715 because 275/5= 55 then 55x13 will give you 715
