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lukranit [14]
3 years ago
10

A 25.0kg girl pushes a 50.0kg boy so that he accelerates at 4.00m/s2. What is the force of the boy on the girl? A. 200N B. 100N

C. 12.5 D. 400N
Physics
1 answer:
Fynjy0 [20]3 years ago
8 0

Answer:

a

Explanation:

so the answer is 200N

and I hope it is correct

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The two things that change are position and speed.
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A small remote-control car with a mass of 1.65 kg moves at a constant speed of v = 12.0 m/s in a vertical circle inside a hollow
Reil [10]

Answer:

N=63.69N

Explanation:

The normal force exerted on the car by the walls of the cylinder at the bottom of the vertical circle will be such that when substracted to the weight it must give the centripetal force, since at that point on the vertical F_{cp}=N-W=N-mg

We also know that the equation for the centripetal force is:

F_{cp}=ma_{cp}=\frac{mv^2}{r}

Mixing both equations we get:

N-mg=\frac{mv^2}{r}

N=mg+\frac{mv^2}{r}

Which for our values means:

N=(1.65Kg)(9.8m/s^2)+\frac{(1.65Kg)(12m/s)^2}{(5m)}=63.69N

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Read 2 more answers
A toy rocket that weights 10 N blasts straight up from ground level with an initial kinetic energy of 40J. at the exact top of i
marishachu [46]

Answer:

14 m

Explanation:

Applying,

P.E = WH............ Equation 1

Where P.E = potential energy at the highest vertical height, W = weight of the toy rocket, H = Vertical height.

Note: At the highest vertical height, the kinetic energy is 0 J

Therefore,

Mechanical energy(M.E) = Potential Energy(P.E)

make H the subject of the equation

H = P.E/W......... Equation 2

From the question,

Given: W = 10 N,  P.E = 140 J

Substitute these values in equation 2

H = 140/10

H = 14 m

8 0
3 years ago
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