Answer:
x = - 1.4
Explanation:
-5=10x+2-5x (subtract 5x from both sides)
-5=5x+2 (simplify)
-5-2=5x (subtract 2 from both sides)
-7=5x (simplify)
x=-7/5 (divide both sides by 5)
x=-1.4 (simplify)
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Answer:
The turnover number of the enzyme molecule bovine carbonic anhydrase = 67,272,727.27 s^–1.
Explanation:
Given:
The concentration of bovine carbonic anhydrase = total enzyme concentration = Et = 3.3 pmol⋅L^–1 = 3.3 × 10^–12 mol.L^–1
The maximum rate of reaction = Rmax (Vmax) = 222 μmol⋅L^–1⋅s^–1 = 222 × 10^–6 mol.L^–1⋅s^–1
The formula for the turnover number of an enzyme (kcat, or catalytic rate constant) = Rmax ÷ Et = 222 × 10^–6 mol.L^–1⋅s^–1 ÷ 3.3 × 10^–12 mol.L^–1 = 67,272,727.27 s^–1
Therefore, the turnover number of the enzyme molecule bovine carbonic anhydrase = 67,272,727.27 s^–1
Answer:
n= 16021.03 slaps
Explanation:
Using law of Energy conservation
E_{thermal}= Kinetic energy of hand
⇒
m_h= mass of the hand = 0.4 kg
v_h= velocity of the hand = 10 m/s
n= number of slaps
c= 4180 J/Kg °C
m= mass of chicken = 1 kg
Assuming all the energy of hand goes into chicken
Given Ti=0°C and T_f= 170 F= 76.66°C
Now putting the values in above equation to get n
n= 16021.03 slaps
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Below are the choices:
only the x component
only the y component
both the x and y components
neither the x nor the y component
The answer is neither the x nor the y component
Answer:
I think it's 0 N 3rd choice
