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makkiz [27]
3 years ago
14

What happens when two sound waves meet in destructive interference?

Physics
1 answer:
Anna71 [15]3 years ago
6 0

sorry i did not mean to answer

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An electric kettle is rated at 2 kW when connected to a 230 V electrical supply
Oliga [24]

Explanation:

a) P = IV

2000 W = I (230 V)

I = 8.7 A

b) The fuse must be rated for a higher current than the kettle, so use the 13A fuse.

c) Double insulation means there are two layers of insulation, insuring that the wires cannot touch the outer casing of the kettle and protecting the user from electrical shock.

d) V = IR

230 V = (8.7 A) R

R = 26.5 Ω

6 0
3 years ago
A 240-volt, 2-amp motor is connected to a three-wire, 120/240-volt system. Connected between the black wire and neutral are four
pantera1 [17]

Answer:

(i)The current flow in black wire = 9.67 A (ii) The current low in the red wire is 9.68 A (iii) The current flow in neutral wire is  15.36 A (iv) when 240 volt were disconnected current  in black wire is 7.68 A (v) when 240 volt were disconnected current in red wire is 7.68 A (vi) 15.36 A (vii) 6.34 (viii) 9.68 A (ix) 12.02 A

Explanation:

Solution

The current drawn by one amp is

I =P/V

I =200/120

I= 1.67 A

(i) The current flow in the black wire  is

IBK = 4 * 1.67 A + 1A + 2A

IBK = 9.67 A

(ii) Current flow in the red wire is

IRD = 3 * 1.67 A + 1.67 A + 1A + 2A

= 8.68A + 1 A = 9.68 A

Note: Kindly find an attached copy of part of the solution to the given question above.

6 0
4 years ago
What is the potential energy of a 3 kilogram-ball that is on the ground?
Aleks [24]
The answer is 0
potential energy= mass• gravity (9.8m/s)• height.
Your mass 3kg. I believe your need to convert this to grams (3000g) and then multiply by 9.8. Since your height is 0 because the ball is on the ground then your potential energy is 0
3 0
3 years ago
Read 2 more answers
An astronaut holds a rock 100m above the surface of Planet X . The rock is then thrown upward with a speed of 15m/s , as shown i
Butoxors [25]

Answer:5 m/s^{2}

Explanation:

The described situation is is related to vertical motion (and free fall). So, we can use the following equation that models what happens with this rock:

y=y_{o}+V_{o}sin\theta t-\frac{1}{2}gt^{2} (1)

Where:

y=0m is the rock's final height

y_{o}=100 m is the rock's initial height

V_{o}=15 m/s is the rock's initial velocity

\theta=90\° is the angle at which the rock was thrown (directly upwards)

t=10 s is the time

g is the acceleration due gravity in Planet X

Then, isolating g and taking into account sin(90\°)=1:

g=(-\frac{2}{t^{2}})(y-y_{o}-V_{o}t) (2)

g=(-\frac{2}{(10 s)^{2}})(0 m-100 m-(15 m/s)(10 s)) (3)

Finally:

g=5 m/s^{2} (4) This is the acceleration due gravity in Planet X

7 0
3 years ago
Answer and I will give you brainiliest <br><br><br><br><br>Please I need a surely answer ​
hichkok12 [17]

Answer:

<h2><u>Constant</u></h2>

Explanation:

Please don't comment in this question's comment box

<h2>Thanks</h2>
8 0
4 years ago
Read 2 more answers
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