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3 years ago

What factor does the material, the amount of it, or its compression play in your egg surviving or not?

1 answer:

jeka943 years ago

5 0

<span> Impulse and momentum are very important factors for engineers when thh Materials•Egg ... the force exerted on the ground) will increase the amount of time that the force ... us to spread the force of the egg evenly for the egg to survive the collision. The less velocity your egg has, the safer the egg will be.</span><span>
</span>

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Mike wants to build an amplifier. Which technology can he use?

Dafna11 [192]

He most likely can use a generator

5 0

3 years ago

A projectile is launched at an angle above the

erica [24]

If we neglect friction/air resistance, then the horizontal component
doesn't change, and the vertical component becomes (9.8 m/s downward)
greater each second thanks to gravity.

So, after 2 seconds, the horizontal component is still 40 m/s, and the
vertical component is (30 - 2·9.8) = 10.4 m/s upward.

Choice #1 says this.

7 0

3 years ago

Sunlight strikes a piece of crown glass at an angle of incidence of 38.0°. Calculate the difference in the angle of refraction b

zhuklara [117]

Answer:

Difference in the angle of refraction = 0.3°

41.04° is the minimum angle of incidence.

Explanation:

Angle of incidence = 38.0°

For yellow light :

Using Snell's law as:

$\frac {sin\theta_2}{sin\theta_1}=\frac {n_1}{n_2}$

Where,

Θ₁ is the angle of incidence

Θ₂ is the angle of refraction

n₁ is the refractive index for yellow light which is 1.523

n₂ is the refractive index of air which is 1

So,

$\frac {sin\theta_2}{sin{38.0}^0}=\frac {1.523}{1}$

${sin\theta_2}=0.9377$

Angle of refraction for yellow light = sin⁻¹ 0.9377 = 69.67°.

For green light :

Using Snell's law as:

$\frac {sin\theta_2}{sin\theta_1}=\frac {n_1}{n_2}$

Where,

Θ₁ is the angle of incidence

Θ₂ is the angle of refraction

n₁ is the refractive index for green light which is 1.526

n₂ is the refractive index of air which is 1

So,

$\frac {sin\theta_2}{sin{38.0}^0}=\frac {1.526}{1}$

${sin\theta_2}=0.9395$

Angle of refraction for green light = sin⁻¹ 0.9395 = 69.97°.

The difference in the angle of refraction = 69.97° - 69.67° = 0.3°

Calculation of the critical angle for the yellow light for the total internal reflection to occur :

The formula for the critical angle is:

${sin\theta_{critical}}=\frac {n_r}{n_i}$

Where,

${\theta_{critical}}$ is the critical angle

$n_r$ is the refractive index of the refractive medium.

$n_i$ is the refractive index of the incident medium.

n₁ is the refractive index for yellow light which is 1.523 (incident medium)

n₂ is the refractive index of air which is 1 (refractive medium)

Applying in the formula as:

${sin\theta_{critical}}=\frac {1}{1.523}$

The critical angle is = sin⁻¹ 0.6566 = 41.04°

5 0

4 years ago

A 0.50-kilogram frog is at rest on the bank surrounding a pond of water. As the frog leaps from the bank, the magnitude of the a

marysya [2.9K]

Complete question:

A 0.50 kilogram frog is at rest on the bank surrounding a pond of water. As the frog leaps from the bank, the magnitude of the acceleration of the frog is 4.0 meters per second^2. Calculate The magnitude of the net force exerted on the frog as it leaps.

Answer:

2.0N

Explanation:

Given that,

Mass, m of the frog = 0.5 kg

The acceleration of the frog = 4.0 m/s².

We have been asked To find,

The magnitude of the net force exerted on the frog as it leaps.

We calculate this using the formula below :

F = ma

When we insert the values into the formula, we have:

F = 0.5 kg × 4 m/s²

F = 2.0 N

Therefore, the magnitude of net force is 2.0 N.

5 0

3 years ago

A timeline is necessary a. For every goal c. For every life goal b. For every academic goal d. For every high school goal please

kiruha [24]

I’d say for every life goal

5 0

3 years ago

Read 2 more answers