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Serga [27]
3 years ago
11

Simplify by combining like terms: 4a + 3(5a - 2)

Mathematics
2 answers:
zaharov [31]3 years ago
4 0

Answer:

19a - 6

Step-by-step explanation:

Scilla [17]3 years ago
4 0

Answer:

4a + 3 ( 5a - 2 )

= 4a + [ 3 ( 5a - 2 ) ]

= 4a + [ 15a - 6 ]

= 4a + 15a - 6

= 19a -6

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A. (0, -6)

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Opposite angles of an inscribed quadrilateral are supplementary?
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In a study of government financial aid for college​ students, it becomes necessary to estimate the percentage of​ full-time coll
algol13

Answer:

(a) The sample size required is 2401.

(b) The sample size required is 2377.

(c) Yes, on increasing the proportion value the sample size decreased.

Step-by-step explanation:

The confidence interval for population proportion <em>p</em> is:

CI=\hat p\pm z_{\alpha/2}\sqrt{\frac{\hatp(1-\hat p)}{n}}

The margin of error in this interval is:

MOE=z_{\alpha/2}\sqrt{\frac{\hatp(1-\hat p)}{n}}

The information provided is:

MOE = 0.02

z_{\alpha/2}=z_{0.05/2}=z_{0.025}=1.96

(a)

Assume that the proportion value is 0.50.

Compute the value of <em>n</em> as follows:

MOE=z_{\alpha/2}\sqrt{\frac{\hat p(1-\hat p)}{n}}\\0.02=1.96\times \sqrt{\frac{0.50(1-0.50)}{n}}\\n=\frac{1.96^{2}\times0.50(1-0.50)}{0.02^{2}}\\=2401

Thus, the sample size required is 2401.

(b)

Given that the proportion value is 0.55.

Compute the value of <em>n</em> as follows:

MOE=z_{\alpha/2}\sqrt{\frac{\hat p(1-\hat p)}{n}}\\0.02=1.96\times \sqrt{\frac{0.55(1-0.55)}{n}}\\n=\frac{1.96^{2}\times0.55(1-0.55)}{0.02^{2}}\\=2376.99\\\approx2377

Thus, the sample size required is 2377.

(c)

On increasing the proportion value the sample size decreased.

8 0
4 years ago
Can someone answer this too?!?!
Ksenya-84 [330]
1/6 plus 2/3 = 5/6 so you do 24 - 5/6 which is 23 1/6
8 0
4 years ago
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