Answer:
n(HCl)=1.96 mol
Explanation:
CH4+4Cl2⟶CCl4+4HCl
CCl4+2HF⟶CCl2F2+2HCl
With ideal yields we will end up with 4 moles of HCl.
With 70% yields on every stage
n(HCl)=0.7*0.7*4=1.96 mol
The answer is (b). As, vanadium is attached to five fluoride atoms, each flouride containing -1 oxidation state, hence five fluoride contains -5, to neutralize, vanadium should have +5 oxidation state.
Explanation:
first of all open the menu
Answer:
The yearly release of
into the atmosphere is
.
Explanation:

Annual production of CaO = 
Moles of CaO :

According to reaction, 1 mole of CaO is produced along with 1 mole of carbon-dioxide.
Then along with
of CaO moles of carbon-dioxide moles produced will be:
of carbon-dioxide
Mass of
moles of carbon-dioxide:

The yearly release of
into the atmosphere is
.