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CaHeK987 [17]
2 years ago
7

Helppppppppppp!!!!!!!!!!!

Mathematics
1 answer:
Fed [463]2 years ago
6 0
A parallel line must have the same slope. The only one it can be is A
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Consider the plane, T, and three collinear points (but not coplanar) points P, Q, and W.
Montano1993 [528]

Answer:

vvv dvw

Step-by-step explanation:

dnbvfv nb f

5 0
3 years ago
PLZ HELP I WILL GIVE BRAINLYEST AND 100 POINTS IF YOUR CORRECT
Sav [38]

Answer:

3

Step-by-step explanation:

i double checked

4 0
2 years ago
Read 2 more answers
Taisha uses the elliptical cross- trainer at the gym. Her general goal is to burn 280 calories per workout, but she varies by as
Fed [463]

Given - Taisha has a general goal is to burn the 280 calories.

she is varies by the 25 calories.

Find out the maximum and minimum of calories burn by the taisha.

To proof -

let us assume that the calories burn by the taisha be x.

as given the calories are varies by the 25 calories.

then the maximum calories equation becomes

x-25 = 280

x = 280 + 25

x = 305

the maximum calories burn by the taisha is 305 calories.

minimum calories equationbecomes

x + 25 = 280

x = 255

The minmum calories burn by the taisha is 255 calories.

Hence proved






8 0
3 years ago
Read 2 more answers
Which inequality represents the problem?
kogti [31]
I believe A is correct.
8 0
3 years ago
5w²-5w=0 . -10n²+35n=0 . 2x²+15x=0 . 18c²+6c=0 . -32y²-24y=0
love history [14]

5 {w}^{2}  - 5w = 0\Leftrightarrow 5w(w - 1) = 0\Leftrightarrow w = 0 \: \vee \: w = 1 \\  - 10 {n}^{2}  + 35n = 0\Leftrightarrow  - 5n(2n - 7) = 0\Leftrightarrow n = 0 \: \vee \: n =  \frac{7}{2}  \\ 2 {x}^{2}  + 15x = 0\Leftrightarrow x(2x + 15) = 0\Leftrightarrow x = 0 \: \vee \: x =  \frac{15}{2}  \\ 18 {c}^{2}  + 6c = 6c(3c + 1) = 0\Leftrightarrow c = 0  \: \vee \: c =  -  \frac{1}{3}  \\  - 32 {y}^{2}  - 24y = 0\Leftrightarrow  - 8y(4y + 3) = 0\Leftrightarrow y = 0 \:\vee \: y =  -  \frac{3}{4}  \\ 3 {k}^{2}  = 6k\Leftrightarrow k = 0 \: \vee \: k = 2 \\ 6 {h}^{2}  = 3h\Leftrightarrow h = 0 \: \vee \: h =  \frac{1}{2}  \\ 4 {s}^{2}  = 10s\Leftrightarrow s = 0 \: \vee \: s =  \frac{5}{2}  \\  - 42 {z}^{2}  = 14z\Leftrightarrow z = 0 \:\vee \: z =  -  \frac{1}{3}

6 0
3 years ago
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