3. There are 4 friends. A quarter of 4 is 25%. You can prove this by multipling 25% by 4 of the friends to get 100%. There is a 25% chance of Jonathon arriving first and a 25% chance that Michel will arrive second.
Answer:
No
Step-by-step explanation:
Using the converse of Pythagoras' identity.
If the longest side squared is equal to the sum of the squares of the other 2 sides then the triangle is right.
The longest side = 61, thus
61² = 3721
12² + 60² = 144 + 3600 = 3744 ≠ 3721
Thus these sides do not form a right triangle.
Answers:
- Part A) There is one pair of parallel sides
- Part B) (-3, -5/2) and (-1/2, 5/2)
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Explanation:
Part A
By definition, a trapezoid has exactly one pair of parallel sides. The other opposite sides aren't parallel. In this case, we'd need to prove that PQ is parallel to RS by seeing if the slopes are the same or not. Parallel lines have equal slopes.
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Part B
The midsegment has both endpoints as the midpoints of the non-parallel sides.
The midpoint of segment PS is found by adding the corresponding coordinates and dividing by 2.
x coord = (x1+x2)/2 = (-4+(-2))/2 = -6/2 = -3
y coord = (y1+y2)/2 = (-1+(-4))/2 = -5/2
The midpoint of segment PS is (-3, -5/2)
Repeat those steps to find the midpoint of QR
x coord = (x1+x2)/2 = (-2+1)/2 = -1/2
y coord = (x1+x2)/2 = (3+2)/2 = 5/2
The midpoint of QR is (-1/2, 5/2)
Join these midpoints up to form the midsegment. The midsegment is parallel to PQ and RS.
A rhombus has four equal sides. If the perimeter of this rhombus is 164, then the length of one side is 164/4, or 41.
Draw this rhombus. Label all four sides with "41." Label the longer diagonal 80 and the half length of that diagonal 40. You will see inside the rhombus four congruent triangles with hypotenuse 41, leg 10 and unknown height. Thus, this unknown height is found by solving x^2 + 40^2 = 41^2, and x^2=9, so that the length of the shorter diagonal is 2(2) = 18 (answer).
<span>He bought 36 baseball cards. Since 3/4 of the 48 cards are baseball cards, you need to find 75% of 48, which is 36 cards. </span>
