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2 years ago

6

In a middle school orchestra, there are 6 sixth graders, 11 seventh graders, and 8 eight graders. If one student is randomly cho

sen to complete a solo, what is the probability that a seventh grader is chosen?

1 answer:

padilas [110]2 years ago

8 0

Answer:

11/25

Step-by-step explanation:

total number of students to selet from is 6+11+8=25

number of seventh graders is 11

=11/25

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Sharnae raised $52 less than lee during a school fundraiser. Lee raised $384. How much did sharnae raised?

neonofarm [45]

Answer:

$352

Step-by-step explanation:

So subtract the amount Lee made from the $52 and you get your answer. i hope i help u

6 0

2 years ago

What is interest earned on 3500 invested at 6% compounded quarterly or 12 years

enyata [817]

$\bf \qquad \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to &\$3500\\
r=rate\to 6\%\to \frac{6}{100}\to &0.06\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{quarterly, thus four}
\end{array}\to &4\\
t=years\to &12
\end{cases}
\\\\\\
A=3500\left(1+\frac{0.06}{4}\right)^{4\cdot 12}\implies A=3500(1.015)^{48}$

so, the interest earned then will be A - 3500.

6 0

2 years ago

For history class, Joe spent 2 hours writing a 4-page report on ancient Egypt. This weekend, he needs to write a 12-page report

Natalka [10]

Answer:

2hours/4pages

2/4=1/2

1/2=x/12

cross multiply

12=2x

divide by 2 both sides

6=x

6 hours

3 0

2 years ago

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A student S is suspected of cheating on exam, due to evidence E of cheating being present. Suppose that in the case of a cheatin

Kay [80]

Answer:

Step-by-step explanation:

Suppose we think of an alphabet X to be the Event of the evidence.

Also, if Y be the Event of cheating; &

Y' be the Event of not involved in cheating

From the given information:

$P(\dfrac{X}{Y}) = 60\% = 0.6$

$P(\dfrac{X}{Y'}) = 0.01\% = 0.0001$

$P(Y) = 0.01$

Thus, $P(Y') \ will\ be = 1 - P(Y)$

P(Y') = 1 - 0.01

P(Y') = 0.99

The probability of cheating & the evidence is present is = P(YX)

$P(YX) = P(\dfrac{X}{Y}) \ P(Y)$

$P(YX) =0.6 \times 0.01$

$P(YX) =0.006$

The probabilities of not involved in cheating & the evidence are present is:

$P(Y'X) = P(Y') \times P(\dfrac{X}{Y'})$

$P(Y'X) = 0.99 \times 0.0001 \\ \\ P(Y'X) = 0.000099$

(b)

The required probability that the evidence is present is:

P(YX or Y'X) = 0.006 + 0.000099

P(YX or Y'X) = 0.006099

(c)

The required probability that (S) cheat provided the evidence being present is:

Using Bayes Theorem

$P(\dfrac{Y}{X}) = \dfrac{P(YX)}{P(Y)}$

$P(\dfrac{Y}{X}) = \dfrac{P(0.006)}{P(0.006099)}$

$P(\dfrac{Y}{X}) = 0.9838$

5 0

2 years ago

5. Evaluate the quadratic function f(x) = 5(x-3)(x-2) when x = 9

tatyana61 [14]

Answer:

Step-by-step explanation:

f(9)=5(9-3)(9-2)

=5*6*7

=210

7 0

2 years ago

Read 2 more answers