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Lelu [443]
3 years ago
14

Sarah starts a Jewelry making business. She borrows the money for the supplies to start. She borrows $1,500.00 for 2 years at a

simple interest rate
of 12 percent. At the end of the 2 years, how much interest would be paid?
O $360.00
O $600.00
$300.00
O $240.00
Mathematics
1 answer:
LuckyWell [14K]3 years ago
3 0
O would be the answer, but I’m not sure why you have 3
(360.00 to be exact)
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Need help with the answer plz
Shtirlitz [24]
Multiply the previous value by 3
6 0
4 years ago
Use the translation (x, y)→(x−4, y+2) to find the preimage of (7, 2)
Bess [88]

Answer:

(11 , 0)

Step-by-step explanation:

x - 4 = 7

x = 7 +4

x = 11

           y + 2 = 2

                y = 2 - 2

                 y = 0

6 0
2 years ago
A. 2 (2)(3)(3)(a)(a)(a)(a)(a)(a)(a)(a)3(3)(5)(5)(a)(a)
marishachu [46]

Answer:

  • E. 2/5 a³

Step-by-step explanation:

  • \sqrt{36a^8/225a^2} =                       simplify
  • \sqrt{4a^6/25} =                              square root
  • 2/5 a³

Also possible option is B if 4a⁶/25 is under root

8 0
2 years ago
Read 2 more answers
Consider a drug testing company that provides a test for marijuana usage. Among 317 tested​ subjects, results from 25 subjects w
svet-max [94.6K]

Answer:

We conclude that we fail to reject H_0 as there is not sufficient evidence to warrant support of the claim that less than 10 percent of the test results are wrong.

Step-by-step explanation:

We are given that among 317 tested​ subjects, results from 25 subjects were wrong.

We have to test the claim that less than 10 percent of the test results are wrong.

<u><em>Let p = proportion of subjects that were wrong.</em></u>

So, Null Hypothesis, H_0 : p = 10%     {means that 10 percent of the test results are wrong}

Alternate Hypothesis, H_A : p < 10%     {means that less than 10 percent of the test results are wrong}

The test statistics that would be used here <u>One-sample z proportion</u> <u>statistics</u>;

                      T.S. =  \frac{\hat p-p}{\sqrt{\frac{\hat p (1-\hat p)}{n} } }  ~ N(0,1)

where, \hat p = sample proportion of test results that were wrong = \frac{25}{317} = 0.08

           n = sample of tested subjects = 317

So, <u><em>test statistics</em></u>  =  \frac{0.08-0.10}{\sqrt{\frac{0.08 (1-0.08)}{317} } }

                              =  -1.31

The value of z test statistics is -1.31.

Now, the P-value of the test statistics is given by the following formula;

                P-value = P(Z < -1.31) = 1 - P(Z \leq 1.31)

                              = 1 - 0.9049 = <u>0.095</u>

<u><em>Now, at 0.05 significance level the z table gives critical value of -1.645 for left-tailed test.</em></u><em> Since our test statistics is more than the critical value of z as -1.31 > -1.645, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which </em><em><u>we fail to reject our null hypothesis</u></em><em>.</em>

Therefore, we conclude that we fail to reject H_0 as there is not sufficient evidence to warrant support of the claim that less than 10 percent of the test results are wrong.

5 0
3 years ago
HURRY PLEASE<br> What is the slope of the line on the graph below?<br> -1/2<br> 1/2<br> 1<br> 2
fomenos

Answer:

the answer is definitely 2

7 0
3 years ago
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