The number of terms in the given arithmetic sequence is n = 10. Using the given first, last term, and the common difference of the arithmetic sequence, the required value is calculated.
<h3>What is the nth term of an arithmetic sequence?</h3>
The general form of the nth term of an arithmetic sequence is
an = a1 + (n - 1)d
Where,
a1 - first term
n - number of terms in the sequence
d - the common difference
<h3>Calculation:</h3>
The given sequence is an arithmetic sequence.
First term a1 = = 3/2
Last term an = = 5/2
Common difference d = 1/9
From the general formula,
an = a1 + (n - 1)d
On substituting,
5/2 = 3/2 + (n - 1)1/9
⇒ (n - 1)1/9 = 5/2 - 3/2
⇒ (n - 1)1/9 = 1
⇒ n - 1 = 9
⇒ n = 9 + 1
∴ n = 10
Thus, there are 10 terms in the given arithmetic sequence.
learn more about the arithmetic sequence here:
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Disclaimer: The given question in the portal is incorrect. Here is the correct question.
Question: If the first and the last term of an arithmetic progression with a common difference are , and 1/9 respectively, how many terms has the sequence?
Answer:
20x-21y+14
Step-by-step explanation:
1/5(100x-105y+70)
20x-21y+14
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The length is 6 inches more than the width and the area is 72 so 72÷6 = 12
12 is 6 more than 6 so 12 x 6 = 72 the length will be 12 the width is 6 and the area 72 hope this helps
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Answer:
Approximately 131 days
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Let the store will take x days to sell 174 puppies.
Since, there is a relation of direct proportion between the puppies sold and number of days.
So,