Question

Please help and hurry

Answer 1

Answer:

See below, please

Explanation:

Because the mole ratio

$\frac{m(ch4)}{m(o2)} = \frac{1}{2}$

Now, at the beginning

Mole m(CH4) =4 mol, m(O2) = 5 mol

If O2 gas is fully reacted, used up,

Need m(CH4) = 2.5 mol

Hence, the mole of CH4 left

m(CH4) = 4-2.5=1.5 mol

That means

At the end of the reaction,

m(CH4) =1.5 mol

m(O2) = 0 mol