Answer:
Evening walk is shorter.
Step-by-step explanation:
We have been given that a nature center offers 2 guided walks. The morning walk is two-third mile. The evening walk is three-sixths mile. We are asked to find the shorter walk.
Let us compare both fractions by making the same denominator.




Upon making common denominator, we can see that two-thirds are equal to four sixths.
Since three-sixths is less than four-sixths, therefore, evening walk is shorter.
We will draw two rectangles, one with 6 sub-parts and other with three sub-parts.
We will shade 2 parts out of 3 sub-parts to represent 2/3 and shade 3 parts out of 6 sub-parts to represent 3/6.
Then we will further divide three sub-parts into 6 sub-parts as shown in the diagram that will represent 4/6.
Each ticket costs $7 and on Friday every ticket is discounted by $2 so the cost of every ticket would be $5 on Friday and 5x9=45 so the cost for 9 tickets on Friday is worth $45
Answer:
the answer is 6 since from 1 side to the other it makes 12 you just divide 12 by 2 since O is in the middle and only goes to half of the line
Answer:
the answer you picked in the pictures is the correct one
Answer:
The probability is 
Step-by-step explanation:
From the question we are told that
The percentage that are on time is p = 0.76
The sample size is n = 11
Generally the percentage that are not on time is



The probability that no more than 4 of them were on time is mathematically represented as

=> 

