Average rate=(change in y)/(change in x)
if f(x)=-x/3
r=( f(2)-f(-2) )/(2--2)
r=(-2/3-2/3)/(2+2)
r=(-4/3)/4
r=-4/12
r=-1/3
For a line, this is always true, since all lines have a constant velocity, the average velocity over any interval is equal to the slope.
Answer:
x^(5/6) + 4(x^(7/3))
Step-by-step explanation:
Simplify x to the 1/3 power MULTIPLIED BY (x to the 1/2 power + 2x to the 2 power )
Simplify x^(1/3) × (x^(1/2) + (2x)^2)
= x^(1/3)(x^(1/2)) + x^(1/3)((2x)^2)
= x^(1/3+1/2) + 4(x^(1/3+2))
= x^(5/6) + 4(x^(7/3))
x^(1/3) is y such that y^3 = x
(x^(1/3) × x^(1/3) × x^(1/3)) = x^(1/3+1/3+1/3) = x^1 = x
x^(1/2) = √2 = y such that y^2 = x
(2x)^2 = 4x^2
Answer:
The answer is C y= 2x-1
Step-by-step explanation:
