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Kitty [74]
2 years ago
9

Unknown A melts at 113- 114oC. Known compounds 3-Nitroaniline and 4-Nitrophenol both melt at 112-114 oC. If A is mixed with 3-Ni

troaniline and the melting point becomes broad and depressed, what must A be __________A) 3-Nitroaniline B) 4-Nitrophenol C) Both
Chemistry
1 answer:
Naya [18.7K]2 years ago
4 0

Answer:

C) Both

Explanation:

Whenever we mix any pure form of a compound with some other form of a compound which is not in the other standard pure state, this results in the melting point of mixture to get dispersed and it becomes broad form.

Thus, when a known compound of 3-Nitroaniline mixes with both 3-Nitroaniline and 4-Nitrophenol, the melting point of the compound becomes depressed and board.

Thus the correct option is (C).

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Example: The initial value x  The value you are trying to convert to
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Explain how you determine molar mass of Ca(No3)2
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Answer:

164

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Iron-60 Express your answer as an isotope.
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Isotopes are variants atoms of the same element, having same number of atomic(proton) number but different number of neutrons and mass number.

Considering iron-60

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  • The name  iron-60 also tells us that this particlar  isotope's mass number is 60.  
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Now expressing  as an isotope iron-60 becomes   ⁶⁰₂₆Fe ( very unstable )

Other stable isotopes of Iron include   ⁵⁴₂₆Fe , ⁵⁶₂₆Fe, ⁵⁷₂₆Fe and ⁵⁸₂₆Fe

See more here: brainly.com/question/11236150

4 0
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If we know this is a second-order reaction, what is the rate law?
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Answer:

The rate is a mathematical relationship obtained by comparing reaction rate with reactant concentrations.

6 0
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An endergonic reaction with a Δh and Δs can be changed into an exergonic reaction.
zheka24 [161]

Full question:

This question is incomplete, here it is completed:

An endergonic reaction with a ______ ∆H and a ______ ∆S can be changed into an exergonic reaction by decreasing the temperature.

Option A: negative, positive

Option B: negative, negative

Option C: positive, positive

Option D: positive, negative

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Option B: negative, negative

Explanation:

The change in free energy (ΔG) of a system for a constant-temperature process is

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free energy is the energy available to do work. Thus, if a particular reaction is accompanied by a release of usable energy (that is, <u>ΔG is negative</u><u>), it is said to be</u><u> exergonic</u>. On the other hand, if a reaction consumes energy (that is, <u>ΔG is positive</u><u>), it is said to be </u><u>endergonic</u>.

Looking at the equation, we can see that if ΔH is negative and ΔS is negative, then ΔG will be negative only when TΔS  is smaller in magnitude than ΔH. This condition is met when T is small.

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           -        -

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4 0
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