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azamat
3 years ago
10

Help Plzzzzzz!!!!!!!

Chemistry
2 answers:
Reil [10]3 years ago
8 0
A Is the answer babez a:)
lara [203]3 years ago
6 0

Answer:

A

Explanation:

your welcome have a great day.

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If I use the dropper to add 10 mL of drink mix to 50 mL of water, what is the
Yuliya22 [10]

Answer:

16.7%

Explanation:

From the question given above, the following data were obtained:

Volume of drink mix = 10 mL

Volume of water = 50 mL

Percentage of drink mix =?

Next, we shall determine the total volume of the solution. This can be obtained as follow:

Volume of drink mix = 10 mL

Volume of water = 50 mL

Total volume of solution =?

Total volume of solution = (Volume of drink mix) + (Volume of water)

Total volume of solution = 10 + 50

Total volume of solution = 60 mL

Finally, we shall determine the percentage of the drink mix in the solution. This can be obtained as follow:

Volume of drink mix = 10 mL

Total volume of solution = 60 mL

Percentage of drink mix =?

Percentage of drink mix = Vol. of drink mix / total volume × 100

Percentage of drink mix = 10/60 × 100

Percentage of drink mix = 16.7%

4 0
3 years ago
How many moles are present in 54.8 mL of mercury if the density of mercury is 13.6 g/mL?​
lesya692 [45]

Answer:

3.72 mol Hg

General Formulas and Concepts:

<u>Chemistry - Atomic Structure</u>

  • Reading a Periodic Table
  • Using Dimensional Analysis
  • Density = Mass over Volume

Explanation:

<u>Step 1: Define</u>

D = 13.6 g/mL

54.8 mL Hg

<u>Step 2: Identify Conversions</u>

Molar Mass of Hg - 200.59 g/mol

<u>Step 3: Find</u>

13.6 g/mL = x g / 54.8 mL

x = 745.28 g Hg

<u>Step 4: Convert</u>

<u />745.28 \ g \ Hg(\frac{1 \ mol \ Hg}{200.59 \ g \ Hg} ) = 3.71544 mol Hg

<u>Step 5: Check</u>

<em>We are given 3 sig figs. Follow sig fig rules and round.</em>

3.71544 mol Hg ≈ 3.72 mol Hg

8 0
3 years ago
Can someone help me with this molar mass problem?[It’s the last one]
quester [9]

Answer:

54.18 \times 10^{23} \ moles in 3 mole of  Al_2(SO_4)_3

Explanation:

It is clear that in the given 1\ mole of Al_2(SO_4)_3 have 3\ ions of SO_4^2^-

Therefore 3 moles of Al_2(SO_4)_3 will have 3\times3=9 \ ions of   SO_4^2^-

Since 1 ion of anything is equivalent to 6.02\times10^{23} \ moles

Therefore 3 moles of Al_2(SO_4)_3 will have 3\times3=9 \ ions of   SO_4^2^-

Which is equivalent to 9 \times6.02\times10^{23}=54.18\times10^{23} \ moles

Thus 3 moles of  Al_2(SO_4)_3 gives 54.18\times10^{23} \ moles of  SO_4^2^-.

5 0
3 years ago
107.854 how many significant
sattari [20]

Answer:

3

Explanation:

look after DP theres 3 digits

6 0
3 years ago
Name the compound and Determine the number of atoms.<br><br> 22g NH3
Bezzdna [24]

Answer:

Compound is: Ammonia

Number of NH3 Molecules: 7.7905x10^23

Number of N atoms: 7.7905x10^23

Number of H atoms: 2.337x10^24

Explanation:

In order to obtain number of particles: We first need to calculate number of moles which is equal Mass/Molar mass (N=14 H=1)

Thus Number of moles equal 22/14+3 = 1.294117647 Moles

Number of particles equal Number of moles multiply Avogadro's number = 1.294117647 x 6.02x10^23 = 7.7905x10^23 Molecules of NH3

Since that each molecule contains one Nitrogen atom therefore, Number of molecules = number of atoms while each molecule contains 3 Hydrogen atoms therefore, Number of hydrogen atoms = 3x Number of Molecules = 2.337x10^24

4 0
2 years ago
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