Answer:
8.08 × 10⁻⁴
Explanation:
Let's consider the following reaction.
COCl₂(g) ⇄ CO (g) + Cl₂(g)
The initial concentration of phosgene is:
M = 2.00 mol / 1.00 L = 2.00 M
We can find the final concentrations using an ICE chart.
COCl₂(g) ⇄ CO (g) + Cl₂(g)
I 2.00 0 0
C -x +x +x
E 2.00 -x x x
The equilibrium concentration of Cl₂, x, is 0.0398 mol / 1.00 L = 0.0398 M.
The concentrations at equilibrium are:
[COCl₂] = 2.00 -x = 1.96 M
[CO] = [Cl₂] = 0.0398 M
The equilibrium constant (Keq) is:
Keq = [CO].[Cl₂]/[COCl₂]
Keq = (0.0398)²/1.96
Keq = 8.08 × 10⁻⁴
Answer:
1.Products
2.Reactants
3.Activation
4.Chemical potential energy
5.Energy
6.Activated
7.Complex
8.Progress of reaction
9.Enthalpy of Reaction
Explanation:
Relation between molarity and molar mass is as follows.
Molarity = 
It is given that mass is 1 mg/ml which is also equal to
g.
Molecular mass = 58 Da = 58 g/mol
Volume = 1 ml
Therefore, calculate molarity as follows.
Molarity = 
=
= 0.0172 molar
It is known that 1 molar equals 1000 millimolar.
So, 0.0172 molar = 
= 17.2 millimolar
Thus, we can conclude that the concentration of given solution is 17.2 millimolar.