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2 years ago

Calculate the specific heat of a substance if a 35g sample absorbs 48 j as the temperature is raised from 293 k to 313 k

Chemistry

1 answer:

bulgar [2K]2 years ago

8 0

Answer:

c = 0.07 j/g.k

Explanation:

Given data:

Mass of sample = 35 g

Heat absorbed = 48 j

Initial temperature = 293 K

Final temperature = 313 K

Specific heat of substance = ?

Solution:

Specific heat capacity:

It is the amount of heat required to raise the temperature of one gram of substance by one degree.

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT = Final temperature - initial temperature

ΔT = 313 k - 293 K

ΔT = 20 k

Now we will put the values in formula.

48 j = 35 g × c× 20 k

48 j = 700 g.k ×c

c = 48 j/700 g.k

c = 0.07 j/g.k

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2 years ago

Iron 3 oxide and carbon react to form iron and carbon dioxide. Balance the equation.

Oksi-84 [34.3K]

Answer:

2 Fe(iii)2O3 + 3 C ==> 2 Fe + 3 CO2

Explanation:

First of all, you have to translate the words into an equation.

Fe(iii)2O3 + C ==> Fe + CO2

The easiest way to tackle this is to start with the Oxygens and balance them. They must balance by going to the greatest common factor which is 6. So you multiply the molecule by whatever it takes to get the Oxygens to 6

2 Fe(iii)2O3 + C ==> Fe + 3 CO2

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2 Fe(iii)2O3 + C ==> 2 Fe + 3 CO2

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2 Fe(iii)2O3 + 3 C ==> 2 Fe + 3 CO2

And you are done.

5 0

3 years ago

The lab just ran out of 1 M HCl that you need to complete the Benzillic Acid lab. The TA tells you there is 12 M HCl in the fume

Viktor [21]

Answer:

0.83 mL

Explanation:

Given data

Initial concentration (C₁): 12 M

Initial volume (V₁): ?

Final concentration (C₂): 1.0 M

Final volume (V₂): 10.0 mL

We can calculate the initial volume of HCl using the dilution rule.

C₁ × V₁ = C₂ × V₂

V₁ = C₂ × V₂ / C₁

V₁ = 1.0 M × 10.0 mL / 12 M

V₁ = 0.83 mL

The required volume of the initial solution is 0.83 mL.

7 0

3 years ago

For a particular reaction, ΔH = -99.84 kJ and ΔS = -16.80 J/K. Calculate ΔG for this reaction at 298 K.

marta [7]

To solve this given problem, we can use the equation below:
ΔG=ΔH - T*ΔS

We are information and values are given and can be used in solving the ΔG of this particular reaction.
ΔH=-99.84kJ
ΔS=-16.80 J/K
T=298K

ΔG=(-99.84kJ)-(298K*-16.80J/K)
ΔG=-94.83kJ

The answer for ΔG is -94.83kJ.

7 0

2 years ago

Completion

Snowcat [4.5K]

Answer:

Compress
Fixed
Melts
Melting Point
Freezing Point
High
Crystalline
Lattice
Unit cell
Amorphous solids

Explanation:

Solids tend to be dense and difficult to compress.

They do not flow or take the shape of their containers, like liquids do, because the particles in solids vibrate around fixed points.

When a solid is heated until its particles vibrate so rapidly that they are no longer held in fixed positions, the solid melts.

Melting point is the temperature at which a solid changes to a liquid. The melting and freezing point of a substance are at the same temperature.

In general, ionic solids tend to have relatively high melting points, while molecular solids tend to have relatively low melting points.

Most solids are crystalline

The particles are arranged in a pattern known as a crystal lattice

The smallest subunit of a crystal lattice is the unit cell

Some solids lack an ordered internal structure and are called amorphous solids.

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2 years ago