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I am Lyosha [343]
4 years ago
14

During science class, while studying mixtures, you mix together table salt and sand. Your teacher challenges you to separate the

salt from the sand. What property could you use and how would you use it?
Chemistry
1 answer:
olga2289 [7]4 years ago
7 0
The property to be used is sieving. you get a bowl and a sieve when you pour the sand and salt,the salt being the small particle sieve to the bowl while the sand remain on the sieve as residue
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Suppose that you wanted to determine the density of a small aystal to confirm that is silicon. From the literature, you know sil
Alina [70]

Answer:

Volume of CHCl3 required, V(CHCl3) = 8.02 mL

Volume of CHBr3 required, V(CHBr3) = 11.98 mL

Explanation:

Note: The complete question is incomplete. The complete question is given below:

Suppose now that you wanted to determine the density of a small yellow crystal to confirm that it is silicon. From the literature, you know that silicon has a density of 2.33 g/cm3. How would you prepare 20.0 mL of the liquid mixture having that density from pure samples of CHCl3 (d = 1.492 g/mL) and CHBr3 (d = 2.890 g/mL)? (Note: 1 mL = 1 cm3.)

V(CHCl3) = mL

V(CHBr3) = mL

Density of required mixture of CHCl3 and CHBr3 equals the density of silicon = 2.33 g/mL

Density of CHCl3 = 1.492 g/mL

Density of CHBr3 = 2.890 g/mL

Let the fraction of CHCl3 required be y

Fraction of CHBr3 required will be 1 - y

Density of mixture = ( fraction of CHCl3 * density of CHCl3) + (fraction of CHBr3 * density of CHBr3)

2.33 = (y * 1.492) + (1 - y) * 2.890

2.33 = 1.492y + 2.890 - 2.890y

-0.56 = -1.398y

y = 0.401

Therefore, volume of CHCl3 required = 0.401 * 20 mL = 8.02 mL

Volume of CHBr3 required = (20 - 8.02) = 11.98 mL

8 0
3 years ago
Moles of LiCL.<br> 52.0 g of LiCl represents
Anna007 [38]

Answer:

52.0 g of LiCl represents 1.23 moles of compound

Explanation:

In order to determine the moles of LiCl, we need to know the molar mass of our compound

Molar mass LiCl = Molar mass Li + Molar mass Cl

Molar mass LiCl = 6.94 g/mol + 35.45 g/mol =42.39 g/mol

Now, we can do the conversion:

52 g . 1 mol / 42.39 g/mol = 1.23 moles

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<h2>I hope it will help you. </h2>
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Answer:

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Heating sugar to form caramel.

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