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tangare [24]
3 years ago
7

2. Answer this question: Lava rocks I nature come in different shapes and sizes. What processes do you think are responsible the

diversity in sizes and shapes that lava rocks come in? Weathering? Erosion? A combination? Explain your answer!
Chemistry
1 answer:
GuDViN [60]3 years ago
4 0

Answer: im not sure im only in 8th grade but im pretty sure  Erosion i started learning about this last year i really cant explain it... im still hainving trouble with it.

Explanation:

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Which element is similar to the properties bromine?
Ainat [17]

Answer: Fluorine

Explanation: It belongs in the same group as Bromine

8 0
3 years ago
Henri draws a wave that has a 4 cm distance between the midpoint and the trough. Geri draws a wave that has an 8 cm
OLga [1]

Answer:

I'm thinking Henri's wave and Geri's wave have the same amplitude and energy, but i'm not %100 sure

Explanation:

8 0
3 years ago
Read 2 more answers
25. Which answer best describes the continental rise? area of land that drops toward deep ocean basins 75 mile shallow flat area
Hatshy [7]

Answer:

Thick deposits of sediments carried off of the shelf  

Explanation:

The continental rise is a thick deposit of sediments that accumulate between the continental slope and the abyssal plain

A is wrong. The area of land that drops toward the deep ocean basins is the continental slope.

B is wrong. The 75-mile shallow flat area just off coastlines is the continental shelf.

D is wrong. The surf area along coastlines is the surf zone .

 

8 0
3 years ago
Calculate the standard enthalpy change for the reaction at 25 ∘ 25 ∘ C. Standard enthalpy of formation values can be found in th
WINSTONCH [101]

<u>Answer:</u> The standard enthalpy change of the reaction is coming out to be -16.3 kJ

<u>Explanation:</u>

Enthalpy change is defined as the difference in enthalpies of all the product and the reactants each multiplied with their respective number of moles. It is represented as \Delta H

The equation used to calculate enthalpy change is of a reaction is:  

\Delta H_{rxn}=\sum [n\times \Delta H_f(product)]-\sum [n\times \Delta H_f(reactant)]

For the given chemical reaction:

Mg(OH)_2(s)+2HCl(g)\rightarrow MgCl_2(s)+2H_2O(g)

The equation for the enthalpy change of the above reaction is:

\Delta H_{rxn}=[(1\times \Delta H_f_{(MgCl_2(s))})+(2\times \Delta H_f_{(H_2O(g))})]-[(1\times \Delta H_f_{(Mg(OH)_2(s))})+(2\times \Delta H_f_{(HCl(g))})]

We are given:

\Delta H_f_{(Mg(OH)_2(s))}=-924.5kJ/mol\\\Delta H_f_{(HCl(g))}=-92.30kJ/mol\\\Delta H_f_{(MgCl_2(s))}=-641.8kJ/mol\\\Delta H_f_{(H_2O(g))}=-241.8kJ/mol

Putting values in above equation, we get:

\Delta H_{rxn}=[(1\times (-641.8))+(2\times (-241.8))]-[(1\times (-924.5))+(2\times (-92.30))]\\\\\Delta H_{rxn}=-16.3kJ

Hence, the standard enthalpy change of the reaction is coming out to be -16.3 kJ

6 0
4 years ago
Calculate the average obtained from the following weighings of the same object. Do not forget to include formulas, units, and th
bazaltina [42]

Answer:

10.4376 g

Explanation:

First we <u>calculate the sum of the weighings</u>:

  • 10.4375 g + 10.4381 g + 10.4373 g + 10.4376 g = 41.7505 g

Then we <u>divide the sum by the number of weighings to calculate the average:</u>

  • Number of weighings = 4
  • Average = Sum of weighings / Number of weighings
  • 41.7505 g / 4 = 10.4376 g
6 0
3 years ago
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