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3 years ago

Determine the number of protons neutrons and electrons in 3216s2

Chemistry

1 answer:

Anvisha [2.4K]3 years ago

5 0

Answer:

Number of protons = 16

Number of neutrons = 16

Number of electrons = 18

Explanation:

The atom given is (32,16)S_2.

This simply Sulphur atom.

What (32,16)S_2 implies is that;

Atomic number = 16

Mass number = 32

Now atomic number means number of protons present in the atom

While mass number means number of sum of protons and neutrons present in the atom

Thus;

Number of protons = 16

Number of neutrons = 32 - 16 = 16

Now, for a neutral atom, number of protons is equal to number of electrons.

However, in this case it's not neutral but has a charge of -2.

Thus,

Number of electrons = 16 + 2 = 18 electrons

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Name two hormones produced by the endocrine system and describe how they work with other organ systems to maintain homeostasis

Annette [7]

The 2 hormones are insulin & glucagon.

A hormone will only act on a part of the body it 'fits'. A hormone can be thought of as a key, and its target site ( i.e an organ) has specially shaped locks on the cell walls.
If the hormone fits, then it will work.

The hormone can set off a cascade of other singling pathways in the cell to cause an immediate effect ( for instance, insulin signaling leads to a rapid uptake of glucose in muscle cells)

The endocrine system is a tightly regulated system that keeps the hormones and their effects at just the right level. One way this is achieved is through ' feedback loops'. The release of hormones is regulated by other hormones, proteins or neuronal signals.

The released hormone then has its effect on other organs. This effect on the organ feeds back to the original signal to control any further hormone release.

btw- found all this info @ the Better Health channel, an australian government health website , so if your still confused by my answer, check out this website

www.betterhealth.vic.gov.au/health/conditionsandtreatments/hormonal-endocrine-system

8 0

3 years ago

Read 2 more answers

Write the symbol of another isotope of lead with 132 neutrons.

Ivahew [28]

Answer:

Pb^+7

Explanation:

I placed the carrot there to signify the +7 is supposed to be small. It is plus seven because seven nuetrons are added

5 0

3 years ago

Give the empirical formula for C↓8H↓8

mr_godi [17]

Answer:

Empirical formula of C₈H₈ = CH

Explanation:

Data Given:

Molecular Formula = C₈H₈

Empirical Formula = ?

Solution

Empirical Formula:

Empirical formula is the simplest ration of atoms in the molecule but not all numbers of atoms in a compound.

So,

tha ration of the molecular formula should be divided by whole number to get the simplest ratio of molecule

C₈H₈ Consist of Carbon (C), and Hydrogen (H)

Now

Look at the ratio of these two atoms in the compound

C : H

8 : 8

Divide the ratio by two to get simplest ratio

C : H

8/8 : 8/8

1 : 1

So for the empirical formula is the simplest ratio of carbon to hydrogen 1 : 1

So the empirical formula will be

Empirical formula of C₈H₈ = CH

4 0

3 years ago

The rate constant for a certain reaction is k = 5.40×10−3 s−1 . If the initial reactant concentration was 0.100 M, what will the

IceJOKER [234]

Answer : The concentration after 17.0 minutes will be, $4.05\times 10^{-4}M$

Explanation :

The expression for first order reaction is:

$[C_t]=[C_o]e^{-kt}$

where,

$[C_t]$ = concentration at time 't' (final) = ?

$[C_o]$ = concentration at time '0' (initial) = 0.100 M

k = rate constant = $5.40\times 10^{-3}s^{-1}$

t = time = 17.0 min = 1020 s (1 min = 60 s)

Now put all the given values in the above expression, we get:

$[C_t]=(0.100)\times e^{-(5.40\times 10^{-3})\times (1020)}$

$[C_t]=4.05\times 10^{-4}M$

Thus, the concentration after 17.0 minutes will be, $4.05\times 10^{-4}M$

4 0

3 years ago

You are required to prepare 500 ml of a 6.00 M solution of HNO3 from a stock solution of 12.0 M. Describe in detail how you woul

andriy [413]

Answer: 250 ml of stock solution with molarity of 12.0 M is measured using a pipette and 250 ml of water is added to volumetric flask of 500 ml to make the final volume of 500 ml.

Explanation:

According to the dilution law,

$C_1V_1=C_2V_2$

where,

$C_1$ = concentration of stock solution = 12.0 M

$V_1$ = volume of stock solution = ?

$C_2$ = concentration of diluted solution= 6.00 M

$V_2$ = volume of diluted acid solution = 500 ml

Putting in the values we get:

$12.0\times V_1=6.00\times 500$

$V_1=250ml$

Thus 250 ml of stock solution with molarity of 12.0 M is measured using a pipette and 250 ml of water is added to volumetric flask of 500 ml to make the final volume of 500 ml.

8 0

3 years ago