Explanation:
Certain actions and/or their method can affect the environment, such as leaving the sink on while brushing your teeth or not turning off a light when you leave the room. I personally make decisions to prevent my association with Greenhouse gases by turning off lights when I leave a room, using minimal water, recycling, etc.
Battery or electrochemical cell
Explanation:
A battery is a power source that directs electrons from oxidation - reduction reactions to flow through a device to give electrical power.
- A battery is an electrochemical cell.
- Electrochemical cells are devices in which chemical reactions produce an electric current that is, chemical energy is turned into electrical energy.
- The reactions here are spontaneous redox reactions, hence electrons flows on its own in an external circuit.
learn more:
Battery brainly.com/question/8892837
Atomic battery brainly.com/question/6457557
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Answer:
THE MOLAR MASS OF THE UNKNOWN MOLECULAR SUBSTANCE IS 200 G/MOL.
Explanation:
Mass of the unknown substance = 0.50 g
Freezing point of the solution = 3.9 °C
Freezing point of pure benzene = 5.5 °C
Freezing point dissociation constant Kf = 5.12°C/m
First, calculate the temperature difference between the freezing point of pure benzene and the final solution freezing point.
Change in temperature = 5.5 -3.9 = 1.6 °C
Next is to calculate the number of moles or molarity of the compound that dissolved.
Using the formula:
Δt = i Kf m
Assume i = 1
So,
1.6 °C = 1 * 5.12 * x/ 0.005 kg of benzene
x = 1.6 * 0.008 / 5.12
x = 0.0128 / 5.12
x = 0.0025 moles.
Next is to calculate the molar mass using the formula, molarity = mass / molar mass
Molar mass = mass / molarity
Molar mass = 0.50 g /0.0025
Molar mass = 200 g/mol
Hence, the molar mass of the unknown compound is 200 g/mol
Answer: There are 0.5 grams of barium sulfate are present in 250 of 2.0 M 
solution.
Explanation:
Given: Molarity of solution = 2.0 M
Volume of solution = 250 mL
Convert mL int L as follows.
Molarity is the number of moles of solute present in liter of solution. Hence, molarity of the given solution is as follows.
Thus, we can conclude that there are 0.5 grams of barium sulfate are present in 250 of 2.0 M solution.
