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brilliants [131]
3 years ago
15

A pile of leaves is lit on fire and covered completely with a fire blanket. The fire goes out. Identify the limiting reactant

Chemistry
1 answer:
MAVERICK [17]3 years ago
5 0
Fire blanket i think
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Which of the following represents the electron configuration of s⁻?
GrogVix [38]

Answer:

[Ne] 3s² 3p⁴

Explanation:

4 0
3 years ago
(-15)+(-12)+14<br><br>how do u simplify ​
Lena [83]

Answer:

-15-12-14=-13

Explanation:

we simplify by opening the bracket

5 0
3 years ago
18.2L of gas at 95°C and 760 torr is placed in a 15L container at 80 degrees * C ; what is the new pressure ?
romanna [79]

Answer:

884.56 torr

Explanation:

Formula: \frac{P_{1}V_{1} }{T_{1}} = \frac{P_{2}V_{2} }{T_{2}}

P = Pressure

V = Volume

T = Temperature in kelvin (Celsius + 273.15)

\frac{(760)(18.2) }{368.15} = \frac{P(15) }{353.15}

P = \frac{(760)(18.2)(353.15) }{(368.15)(15)}

P = 884.56169

4 0
3 years ago
Which statement best describes the development of theories that connected microscopic and macroscopic phenomena?
Alina [70]

The statement which best describes the development of theories that connected microscopic and macroscopic phenomena is; <em>q</em><em>It took several hundred years for scientists to develop current theories, and they are still being revised to </em><em>this.</em>

<em>Discussion</em><em>;</em>

Most scientific theories involving microscopic and macroscopic phenomenon have taken several years to be developed; however, this theories are still under revision till date.

Read more:

brainly.com/question/13407374

3 0
2 years ago
How long does it take for a 12.62g sample of ammonia to heat from 209K to 367K if heated at a constant rate of 6.0kj/min? The me
Georgia [21]
First, consider the steps to heat the sample from 209 K to 367K.

1) Heating in liquid state from 209 K to 239.82 K

2) Vaporaizing at 239.82 K

3) Heating in gaseous state from 239.82 K to 367 K.


Second, calculate the amount of heat required for each step.

1) Liquid heating

Ammonia = NH3 => molar mass = 14.0 g/mol + 3*1g/mol = 17g/mol

=> number of moles = 12.62 g / 17 g/mol = 0.742 mol

Heat1 = #moles * heat capacity * ΔT

Heat1 = 0.742 mol * 80.8 J/mol*K * (239.82K - 209K) = 1,847.77 J

2) Vaporization

Heat2 = # moles * H vap

Heat2 = 0.742 mol * 23.33 kJ/mol = 17.31 kJ = 17310 J

3) Vapor heating

Heat3 = #moles * heat capacity * ΔT

Heat3 = 0.742 mol * 35.06 J / (mol*K) * (367K - 239.82K) = 3,308.53 J

Third, add up the heats for every steps:

Total heat = 1,847.77 J + 17,310 J + 3,308.53 J = 22,466.3 J

Fourth, divide the total heat by the heat rate:

Time = 22,466.3 J / (6000.0 J/min) = 3.7 min

Answer: 3.7 min


3 0
3 years ago
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