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brilliants [131]
3 years ago
15

A pile of leaves is lit on fire and covered completely with a fire blanket. The fire goes out. Identify the limiting reactant

Chemistry
1 answer:
MAVERICK [17]3 years ago
5 0
Fire blanket i think
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Which substance would evaporate the fastest at room temperature? (Assume each substance has approximately the same molecular
lutik1710 [3]

Answer:

A non-polar liquid.

Explanation:

Whether a substance dissolves quickly or not depends on how strongly the molecules (or atoms of an element) of a substance are attracted to one another. These interactions between atoms and/or molecules are called intermolecular forces, or IMFs for short. There are several different ones, and these are distinguished from <em>intra</em>molecular forces which are the bonds holding atoms in the molecule together. Attached is a nice little summary of these forces to consider. Our decision lies within the fact that we must pick the substance that experiences the strongest IMF (the one with the most energy). As it turns out, a dipole in a molecule confers some charge distribution on the molecule which makes slightly positive and negative ends. These can attract each other, and it's called dipole-dipole interactions. It can technically happen in a mixture, but let's assume we're dealing with pure substances. Dipoles can only form in polar compounds however, so a non-polar liquid (which is composed of non-polar molecules), will lack these dipoles and therefore cannot form dipole-dipole interactions between the molecules. This results in only having something called dispersion forces (which really every molecule attraction has - so this is the only one). It is very weak, and since the attraction between these molecules is weak, they will tend to come apart, and evaporate. You can think of the IMFs like glue, and a weak glue will not hold the molecules together well, and they will evaporate away.

On the other hand, polar (from dipole interactions) compounds can have general dipole-dipole interactions or hydrogen-bonding interactions (which is a special type of dipole-dipole interaction). H-bonding requires a Hydrogen bonded to either a Nitrogen, Oxygen, or Fluorine to do this. The main thing, is the non-polar ones don't have a dipole, and so they can't form a good intermolecular bond and evaporate quickly.

Water can H-bond, which is why it takes so long to dry and for it to evaporate in general. Nail polish, which is really a solution of acetone, has considerably weaker dipole-dipole bonds (compared to H-bonds), and evaporates quicker than water. Hope this helps!

Note: Figure taken from Chemistry: The Molecular Nature of Matter and Change 8th edition.

3 0
3 years ago
Compare the properties of the following: α particles, cathode rays, protons, neutrons, and electrons.
soldi70 [24.7K]

Properties of the following are:

Alpha particle - positively charged particle (+) that consists of two electrons and two neutrons.

Cathode rays - it is the stream of electrons (negatively charged) found in vacuum.

Protons - are particles that carry positive charge and is present inside the nucleus of an atom.

Electrons - are particles that carry negative charge and is present in the orbits of the atom.

Neutrons - electrically neutral particle (0 charge) present inside the nucleus of an atom. However, it has its own mass.

5 0
3 years ago
Of the two bromoderivatives, C6H5CH(CH3)Br and C6H5CH(C6H5)Br which one is more reactive in SN1 substitution reaction and why?
GrogVix [38]

Answer:

tertiary

Explanation:

tertiary halogenoalkanes are more reactive than primary and secondary as the carbocation is more stable due to alkyl groups( have high electron density) donating electrons to stabilise the carbocation

4 0
3 years ago
In a certain compound of iron and oxygen, FexOy, it is found that a sample of this compound weighing 6.285 g contains 4.396 g of
saveliy_v [14]

Answer:

Formula of oxide is Fe_{2}O_{3}

Explanation:

The given compound consists of Fe and O.

So, mass of oxygen in sample = (mass of sample) - (mass of Fe in sample)

                                                   = (6.285 g ) - (4.396 g)

                                                   = 1.889 g

Molar mass of O = 16 g/mol and molar mass of Fe = 55.845 g/mol

So, ratio of number of moles of Fe and O (Fe : O)

      = \frac{4.396}{55.845}:\frac{1.889}{16}

      = 0.0787 : 0.118

      = 1:\frac{0.118}{0.0787}

      = 1 : 1.5

      = 2 : 3

So, formula of oxide is Fe_{2}O_{3}

5 0
3 years ago
Combustion of 9.511 grams of c4h10 will yield ____ grams of CO2
Flauer [41]

Answer:

\boxed{28.81}

Explanation:

We know we will need an equation with masses and molar masses, so let’s gather all the information in one place.  

M_r:      58.12                   44.01

           2C₄H₁₀ + 13O₂ ⟶ 8CO₂ + 10H₂O

m/g:     9.511

1. Moles of C₄H₁₀

\text{Moles of C$_{4}$H$_{10} $} = \text{ 9.511 g C$_{4}$H$_{10} $} \times \dfrac{\text{1 mol C$_{4}$H$_{10} $}}{\text{ 58.12 g C$_{4}$H$_{10} $}} = \text{0.1636 mol C$_{4}$H$_{10}$}

2. Moles of CO₂

The molar ratio is 8 mol CO₂:2 mol C₄H₁₀

\text{Moles of CO}_{2} =\text{0.1636 mol C$_{4}$H$_{10} $} \times \dfrac{\text{8 mol CO}_{2}}{\text{2 mol C$_{4}$H$_{10}$}} = \text{0.6546 mol CO}_{2}

3. Mass of CO₂

\text{Mass of CO}_{2} = \text{0.6546 mol CO}_{2} \times \dfrac{\text{44.01 g CO}_{2}}{\text{1 mol CO}_{2}} = \textbf{28.81 g CO}_{2}\\\\\text{The combustion will form $\boxed{\textbf{28.81 g CO}_{2}}$}

8 0
3 years ago
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