What must be part of a quantitative observation?

2 answers:

6 0

A quantitative observation must be a measurement of some sort. (Something including numbers). Qualitative, on the other hand, is when you are using words to describe what has happened.

Explanation:

Quantitative observations are performed with devices such as rulers, balances, measured cylinders, beakers, and regulators. These results are measurable,using one or more senses to gather knowledge. information that doesn't involve numbers or measures. the process of making an understanding based on observations and previous knowledge. Quantitative investigations always involve numbers.

cestrela7 [59]3 years ago

5 0

A quantitative observation is an observation obtained from using instruments or tools such as balances, rulers, beakers and thermometers. The results here are measurable. The opposite is called the quantitative observations where the senses are used to see a result.

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Atoms that have a full outer level combine with other atoms. Is this true or false

aev [14]

Answer:

false

Explanation:

some atoms already have a full outer level

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3 years ago

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What is the mass percent of oxygen in sodium bicarbonate (NaHCO3)?

Alenkasestr [34]

The answer is 57.14%.

First we need to calculate molar mass of NaHCO3. Molar mass is mass of 1 mole of a substance. It is the sum of relative atomic masses, which are masses of atoms of the elements.

Relative atomic mass of Na is 22.99 g
Relative atomic mass of H is 1 g
Relative atomic mass of C is 12.01 g
Relative atomic mass of O is 16 g.

Molar mass of NaHCO3 is:
22.99 g + 1 g + 12.01 g + 3 · 16 g = 84 g

Now, mass of oxygen in NaHCO3 is:
3 · 16 g = 48 g

mass percent of oxygen in NaHCO3:
48 g ÷ 84 g · 100% = 57.14%

Therefore, the mass percent of oxygen in sodium bicarbonate is 57.14%.

8 0

3 years ago

Which statement describes the bonds in iron sulfate, FeSO4?

Feliz [49]

___

Regarding the bonds in FesO₄, Fe and S have an ionic bond, while S and O have covalent bonds.

Elements form bonds to increase their stability. The main types of bonds are:

Metallic bonds: they are formed between metals and the electrons are in a delocalized cloud.
Ionic bonds: they are formed between metals (lose electrons) and nonmetals (gain electrons)
Covalent bonds: they are formed between nonmetals, which share electrons.

Regarding the bonds in FesO₄:

Fe is a metal and S a nonmetal, thus they will form ionic bonds.
S and O are both nonmetals, thus they will form covalent bonds.

Regarding the bonds in FesO₄, Fe and S have an ionic bond, while S and O have covalent bonds.

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2 years ago

Given these reactions, X ( s ) + 1 2 O 2 ( g ) ⟶ XO ( s ) Δ H = − 668.5 k J / m o l XCO 3 ( s ) ⟶ XO ( s ) + CO 2 ( g ) Δ H = +

qwelly [4]

Answer: The $\Delta H^o_{rxn}$ for the reaction is -1052.8 kJ.

Explanation:

Hess’s law of constant heat summation states that the amount of heat absorbed or evolved in a given chemical equation remains the same whether the process occurs in one step or several steps.

According to this law, the chemical equation is treated as ordinary algebraic expressions and can be added or subtracted to yield the required equation. This means that the enthalpy change of the overall reaction is equal to the sum of the enthalpy changes of the intermediate reactions.

The given chemical reaction follows:

$X(s)+\frac{1}{2}O_2(g)+CO_2(g)\rightarrow XCO_3(s)$ $\Delta H^o_{rxn}=?$