All categories

3 years ago

HCF AND LCM of 32 and 48 using the prime factorisation

Mathematics

1 answer:

torisob [31]3 years ago

3 0

Answer:

Below.

Step-by-step explanation:

32 = 2*2*2*2*2

48 = 2*2*2*2*3

So The GCF = 2*2*2*2 = 16.

LCM = 2*2*2*2*2*3 = 96

You might be interested in

8n-12=6n+6 I need help figuring out this answer I been having some troble

Gennadij [26K]

Solve the equation with the following steps:
8n-12=6n+6
Subtract 6n from both sides
2n-12=6
Add 12 to both sides
2n=18
Divide both sides by 2
n=9

8 0

3 years ago

PLEASE HELP WITH QUESTION. I am taking a test right now with little time left.

Gwar [14]

1834 bfc I believe that’s the right answer

8 0

3 years ago

Which is the constant term of the algebraic expression -2x2 + 17 -15x + 7xy?

Over [174]

17 is the constant term because it does not have any variables.

5 0

3 years ago

Can someone help me in this question?

igomit [66]

Answer:

3347000 cm is 33.47 km to cm

3347000/64=

401.92 is the circumference

since it is pi * d

do 3347000/401.92

8327.52786624 round to

8327 full revolutions

3 0

3 years ago

Read 2 more answers

Darren wins a coupon for $4 off the lunch special for each of five days he pays $75 for his 5 lunch specials write and solve an

Valentin [98]

The original price for one lunch special is $19.

Explanation

The original price for one lunch special is 'p' dollar.

He wins a coupon for $4 off for each of five days. That means , he needs to pay $(p-4)$ dollar each day.

So, the total amount needed to pay for 5 days $= 5(p-4)$ dollar

Given that, he pays $75 for his 5 lunch specials. So the equation will be.....

$5(p-4)= 75\\ \\ 5p-20=75\\ \\ 5p= 75+20\\ \\ 5p= 95\\ \\ p=\frac{95}{5}=19$

So, the original price for one lunch special is $19.

8 0

3 years ago

HCF AND LCM of 32 and 48 using the prime factorisation​

HCF AND LCM of 32 and 48 using the prime factorisation