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Brilliant_brown [7]
3 years ago
11

Describe how you can find the number of solutions of two or more

Mathematics
1 answer:
Len [333]3 years ago
8 0

Answer:

Suppose we have a system of two linear equations, this can be written as:

y = a*x + b

y = c*x + d

Now, we have 3 possible cases here.

The solutions of the system are the points where the graphs of the linear equations do intersect.

Then, if for example, we have two parallel lines (two parallel lines never intersect) we have no solutions.

And we know that two lines are parallel if they have the same slope and different y-intercept.

Then the system:

y = a*x + b

y = a*x + c

has no solutions.

If we have both equal lines, then the lines intersect in infinitely many points, meaning that we have infinite solutions, then the system:

y = a*x + b

y = a*x +b

has infinite solutions.

And if the lines intersect only one time we have one solution, and this happens when the slopes are different, so the system:

y = a*x + b

y = c*x + d

has only one solution.

Now, if we have more equations:

y = a*x + b

y = c*x + d

y = k*x + n

We have more equations than variables, then this system only has one solution of the 3 lines intersect at the same point, which is really rare.

One case where we have a solution here is if the 3 equations have the same y-intercept:

y = a*x + b

y = c*x + b

y = d*x + b

where the solution is the point (0, b)

Of course, there are other possible solutions, but these are not as formulaic as this ones.

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A bank branch located in a commercial district of a city has the business objective of improving the process for serving custome
choli [55]

Answer:

We conclude that the mean waiting time is more than or equal to 5 minutes at 5% level of significance.

Step-by-step explanation:

We are given that waiting time is defined as the time the customer enters the line until he or she reaches the teller window.  

A random sample of 15 customers is selected. Results found that the sample mean waiting time was 4.287 minutes with a sample standard deviation of 1.638 minutes.

Let \mu = <u><em>mean waiting time.</em></u>

SO, Null Hypothesis, H_0 : \mu \geq 5 minutes     {means that the mean waiting time is more than or equal to 5 minutes}

Alternate Hypothesis, H_A : \mu < 5 minutes      {means that the mean waiting time is less than 5 minutes}

The test statistics that would be used here <u>One-sample t-test statistics</u> as we don't know about population standard deviation;

                              T.S. =  \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }  ~ t_n_-_1

where, \bar X = sample mean waiting time = 4.287 minutes

            s = sample standard deviation = 1.638 minutes

            n = sample of customers = 15

So, <u><em>the test statistics</em></u>  =  \frac{4.287 -5}{\frac{1.638}{\sqrt{15} } }  ~ t_1_4

                                       =  -1.686

The value of t test statistics is -1.686.

Since, in the question we are not given the level of significance so we assume it to be 5%. <u>Now, at 5% significance level the t table gives critical value of -1.761 at 14 degree of freedom for left-tailed test.</u>

Since our test statistic is more than the critical value of t as -1.686 > -1.761, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which <u><em>we fail to reject our null hypothesis</em></u>.

Therefore, we conclude that the mean waiting time is more than or equal to 5 minutes.

5 0
4 years ago
A formula is expressed as D= a(2+kt). Express k in terms of D,a, and t.
Yuri [45]
This is just rearranging terms, it gets kind of ugly though. Start by dividing both sides by a to get D/a=2+kt, next move the 2 over to the left to get (D/a)-2=kt, finally divide the whole expression by t to get ((D/a)-2)/t=k
5 0
4 years ago
What is the mean of this sample, which consists of 10
In-s [12.5K]

Answer:

The mean of the samples is 21

Step-by-step explanation:

Mean is defined as the average sum of numbers i.e total sum of given numbers divided by the total number.

Given the randomly selected numbers as shown;

7, 100, 1, 3, 7, 10, 15, 12, 17, 38

Total sum of numbers = 7+ 100 + 1 + 3 + 7 + 10 + 15 + 12 + 17 + 38

= 210

Total numbers given = 10

Mean = 210/10

Mean = 21

7 0
4 years ago
Find the total value of the investment after the time given
Annette [7]

Answer:mm

13)30187.802

14)1837.565

15)1446.336

16)74008

17)33297.293

18)34972.978

19)13817.6

20)155.589

Step-by-step explanation:

13)18000*1.09to the power of 6

14)1500*1.07³

15)1240*1.08²

16)55000*1.16²

17)28600*1.079²

18)21000*1.136to the power of 4

19)12700*1.088

20)130*1.094²

4 0
3 years ago
Find the area of the figure to the nearest tenth.
jenyasd209 [6]

Answer:

99.0 in²

Step-by-step explanation:

The area (A) of the sector of the circle is calculated as

A = area of circle × fraction of circle

  = πr² × \frac{140}{360} ( where r is the radius )

Here r = 9, thus

A = π × 9² × \frac{14}{36}

   = 81π × \frac{14}{36} ≈ 99.0 in²

3 0
4 years ago
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