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2 years ago

I really need help on this thi g is hard

Mathematics

1 answer:

Katarina [22]2 years ago

5 0

Answer:

Step-by-step explanation:

A division between two roots that have the same index can be rewritten as a division between the two terms with a unic root

$\sqrt{7x^2/3x} = \sqrt{7x/3}$

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1 + 1/2+ 1/3 + 1/6 =

Alenkinab [10]

Answer:

Step-by-step explanation:

I'm not good at explaining it I just know that answer

5 0

3 years ago

Read 2 more answers

Find the slope of the line on the graph

Svetllana [295]

Answer:

m = 1/2

Step-by-step explanation:

Use two points on the line given.

(0 , 2) & (-4 , 0)

You are solving for the slope. The slope formula:

m (slope) = (y₂ - y₁)/(x₂ - x₁)

Let:

(x₁ , y₁) = (-4 , 0)

(x₂ , y₂) = (0 , 2)

Plug in the corresponding numbers to the corresponding variables:

m = (2 - 0)/(0 - (-4))

Simplify:

m = (2)/( 0 - (-4))

m = (2)/(0 + 4)

m = 2/4

Simplify the slope. Divide the common factor 2 from both the numerator and denominator:

m = (2/4)/(2/2) = 1/2

1/2 is your slope.

5 0

3 years ago

Read 2 more answers

Evaluate the triple integral ∭ExydV where E is the solid tetrahedon with vertices (0,0,0),(5,0,0),(0,9,0),(0,0,4).

Elan Coil [88]

Answer: $\int\limits^a_E {\int\limits^a_E {\int\limits^a_E {xy} } \, dV$ = 1087.5

Step-by-step explanation: To evaluate the triple integral, first an equation of a plane is needed, since the tetrahedon is a geometric form that occupies a 3 dimensional plane. The region of the integral is in the attachment.

An equation of a plane is found with a point and a normal vector. Normal vector is a perpendicular vector on the plane.

Given the points, determine the vectors:

P = (5,0,0); Q = (0,9,0); R = (0,0,4)

vector PQ = (5,0,0) - (0,9,0) = (5,-9,0)

vector QR = (0,9,0) - (0,0,4) = (0,9,-4)

Knowing that cross product of two vectors will be perpendicular to these vectors, you can use the cross product as normal vector:

n = PQ × QR = $\left[\begin{array}{ccc}i&j&k\\5&-9&0\\0&9&-4\end{array}\right]$ $\left[\begin{array}{ccc}i&j\\5&-9\\0&9\end{array}\right]$

n = 36i + 0j + 45k - (0k + 0i - 20j)

n = 36i + 20j + 45k

Equation of a plane is generally given by:

$a(x-x_{0}) + b(y-y_{0}) + c(z-z_{0}) = 0$

Then, replacing with point P and normal vector n:

$36(x-5) + 20(y-0) + 45(z-0) = 0$

The equation is: 36x + 20y + 45z - 180 = 0

Second, in evaluating the triple integral, set limits:

In terms of z:

$z = \frac{180-36x-20y}{45}$

When z = 0:

$y = 9 + \frac{-9x}{5}$

When z=0 and y=0:

x = 5

Then, triple integral is:

$\int\limits^5_0 {\int\limits {\int\ {xy} \, dz } \, dy } \, dx$

Calculating:

$\int\limits^5_0 {\int\limits {\int\ {xyz} \, dy } \, dx$

$\int\limits^5_0 {\int\limits {\int\ {xy(\frac{180-36x-20y}{45} - 0 )} \, dy } \, dx$

$\frac{1}{45} \int\limits^5_0 {\int\ {180xy-36x^{2}y-20xy^{2}} \, dy } \, dx$

$\frac{1}{45} \int\limits^5_0 {90xy^{2}-18x^{2}y^{2}-\frac{20}{3} xy^{3} } \, dx$

$\frac{1}{45} \int\limits^5_0 {2430x-1458x^{2}+\frac{94770}{125} x^{3}-\frac{23490}{375}x^{4} } \, dx$

$\frac{1}{45} [30375-60750+118462.5-39150]$

$\int\limits^5_0 {\int\limits {\int\ {xyz} \, dy } \, dx$ = 1087.5

The volume of the tetrahedon is 1087.5 cubic units.

3 0

3 years ago

5 + 8(3 + x) = = Simplify the expression

alisha [4.7K]

Answer:

29 + 8x

Step-by-step explanation:

5 + 8(3 + x) by PEDMAS parentheses first

= 5 + 3(8) + x(8)

= 5 + 24 + 8x

= 29 + 8x

3 0

2 years ago

Please help 2y+x=-15 y=2x

Eva8 [605]

Answer: x = -3

Step-by-step explanation:

2y + x = -15

y = 2x

2y = 2(2x) = 4x

4x + x = -15

5x = -15

x = -3

5 0

2 years ago