Step-by-step explanation:
sec⁴A + tan⁴A = 1 + (2tan²A/cos²A)
LHS = sec⁴A + tan⁴A
= (sec²A)² + (tan²A)² {using formula of a²+b²)
= (sec²A-tan²A) + 2tan²A.sec²A
= 1 + {2tan²A.(1/cos²A)}
= 1 + (2tan²A/cos²A)
Answer:
3- 3, 6, 9, 12, 15, 18, 21, 24, 27, 30
4- 4, 8, 12, 16, 20, 24, 28, 32, 36, 40
7- 7, 14, 21, 28, 35, 42, 49, 56, 63, 70
HOPE IT HELPED
12
hope u find this helpfull
