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denpristay [2]
3 years ago
10

Help me to solve this fast ( prove it)

Mathematics
1 answer:
Harrizon [31]3 years ago
7 0

Step-by-step explanation:

sec⁴A + tan⁴A = 1 + (2tan²A/cos²A)

LHS = sec⁴A + tan⁴A

= (sec²A)² + (tan²A)² {using formula of a²+b²)

= (sec²A-tan²A) + 2tan²A.sec²A

= 1 + {2tan²A.(1/cos²A)}

= 1 + (2tan²A/cos²A)

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