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MA_775_DIABLO [31]
3 years ago
13

Solid aluminum (AI) and oxygen (0) gas react to form solid aluminum oxide (AIO). Suppose you have 7.0 mol of Al and 13.0 mol of

o, in a reactor. Suppose as much as possible of the Al reacts. How much will be left? Round your answer to the nearest 0.1 mol mol 0.
Chemistry
1 answer:
morpeh [17]3 years ago
8 0

Answer:

n_{O_2}^{leftover}=7.7mol

Explanation:

Hello there!

In this case, according to the given information, it turns out firstly necessary for us to set up the corresponding chemical equation:

4Al+3O_2\rightarrow 2Al_2O_3

In such a way, we calculate the moles of aluminum consumed by 13.0 moles of oxygen in the reaction, by applying the 4:3 mole ratio between them:

n_{Al}=13.0molO_2*\frac{4molAl}{3molO_2} =17.3molAl

This means that Al is actually the limiting reactant and oxygen is in excess, for that reason we calculate the moles of oxygen consumed by 7.0 moles of aluminum:

n_{O_2}=7.0molAl*\frac{3molO_2}{4molAl} =5.3molO_2

Thus, the leftover of oxygen is:

n_{O_2}^{leftover}=13.0mol-5.3mol\\\\n_{O_2}^{leftover}=7.7mol

Whereas all the aluminum is assumed to be consumed.

Regards!

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Why does increasing the temperature make a solid dissolve faster?
Deffense [45]

Answer:

The chemical bonds of the solid are broken faster.

Explanation:

As the temperature of a solution is increased, the average kinetic energy of the molecules that make up the solution also increases. The increased vibration (kinetic energy) of the solute molecules causes them to be less able to hold together, and thus they dissolve more readily.

6 0
3 years ago
Elements in group 1A all:
My name is Ann [436]

Answer:

The answer to your question is below

Explanation:

Elements in group 1A all:

a. gain 1 electron   This option is wrong, elements in group 1A loses one electron.

<u>b. lose 1 electron  </u><u>This option is right.</u>

c. are non-metals  This option is incorrect, elements in group IA, are metals.

d. have 2 energy levels This option is incorrect, only one element in each group has 2 energy levels.

8 0
4 years ago
How many grams of O2 are needed to react with 8.15 g of C2H2?
xxTIMURxx [149]

Answer:

25.08 grams of O₂ are needed to react with 8.15 g of C₂H₂.

Explanation:

The balanced reaction is:

2 C₂H₂ + 5 O₂ → 4 CO₂ + 2 H₂O

By reaction stoichiometry, the following amounts of moles of each compound participate in the reaction:

  • C₂H₂: 2 moles
  • O₂: 5 moles
  • CO₂: 4 moles
  • H₂O: 2 moles

The molar mass of each compound is:

  • C₂H₂: 26 g/mole
  • O₂: 32 g/mole
  • CO₂: 44 g/mole
  • H₂O: 18 g/mole

Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

  • C₂H₂: 2 moles* 26 g/mole= 52 g
  • O₂: 5 moles* 32 g/mole= 160 g
  • CO₂: 4 moles* 44 g/mole= 176 g
  • H₂O: 2 moles* 18 g/mole= 36 g

Then you can apply the following rule of three: if by stoichiometry 52 grams of C₂H₂ react with 160 grams of O₂, 8.15 grams of C₂H₂ react with how much mass of O₂?

mass of O_{2} =\frac{8.15 grams of C_{2} H_{2}*160 grams of O_{2}  }{52 grams of C_{2} H_{2}}

mass of O₂= 25.08 grams

<u><em>25.08 grams of O₂ are needed to react with 8.15 g of C₂H₂.</em></u>

8 0
3 years ago
Calculate the molar solubility of lead thiocyanate in pure water. The molar solubility is the maximum amount of lead thiocyanate
OLga [1]

Answer:

Molar solubility(S)=1.71\times10^{-2} mole/litre

Explanation:

Assume Ksp of Pb(SCN)_{2}=2\times10^{-5}( it is general value ,i took it because not given in question)

molar solubilty means how much maximum mole of lead thiocynate is dissolved in one litre of solvent.

Ksp=solubility product;

Pb(SCN)_2= Pb^{2+}  +2SCN^-

Lets molar solubilty of Pb(SCN)_2 is S then

[Pb^{+2}]=S;

[SCN^{-1} ]=2S;

Ksp =S\times(2S)^{2} =2\times10^{-5}

4S^{3}=2\times10^{-5}

S=1.71\times10^{-2} mole/litre

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Ugo [173]

Answer:

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Explanation:

3 0
3 years ago
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