Answer:
209.98 g of NaOH
Explanation:
We are given;
- Volume of HCl as 3 L
- Molarity of HCl as 1.75 M
We are required to calculate the mass of NaOH required to completely neutralize the acid given.
First, we write a balanced equation for the reaction between NaOH and HCl
That is;
NaOH + HCl → NaCl + H₂O
Second, we determine the number of moles of HCl
Number of moles = Molarity × Volume
= 1.75 M × 3 L
= 5.25 moles
Third, we use the mole ratio to determine the moles of NaOH
From the reaction,
1 mole of NaOH reacts with 1 mole of HCl
Therefore;
Moles of NaOH = Moles of HCl
= 5.25 moles
Fourth, we determine the mass of NaOH
Molar mass of NaOH = 39.997 g/mol
Mass of NaOH = 5.25 moles × 39.997 g/mol
= 209.98 g
Thus, 209.98 g of NaOH will completely neutralize 3L of 1.74 M HCl
Answer:
answer is given below
Explanation:
Upper airway obstruction with tongue closure may be associated with damage Changes in alertness and level of consciousness. Clients with severe hypoxia (O2)
Saturation of 40 mm Hg and this is an emergency for hypercapnic (CO2 saturation of 75 mm Hg)
Tracheotomy for relief in 2 minutes. Laryngeal repair is performed to prevent laryngeal.
Cover cartilage cover. Clears the upper airway obstruction due to abdominal thrust maneuvering Foreign body. Autoradiating positive airway pressure resets full pressure during breathing
Users with severe sleep apnea
Fe2O3 because O has a -2 charge and Fe and +3, you want the charges to equal each other so if you have 2 Fe with +3 charge the charge becomes 6 if you have 3 O with -2 charge the charge becomes 6.
Answer:
Correct answer is option (3) .
Explanation:
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