<h3>
Answer:</h3>
272.43 K or -0.718°C
<h3>
Explanation:</h3>
We are given;
The initial pressure,P1 as 761 mmHg
Initial temperature, T1 as 0.00°C which is equivalent to 273.15 K
Final pressure as 759 mmHg
We are required to calculate the final temperature;
According to pressure law, the pressure of a gas and absolute temperature are directly proportional at constant volume.
That is; Pα T
Therefore, at varying pressure and temperature,
To get final temperature;
Therefore, the final temperature will be 272.43 K or -0.718°C
Okay so,
1) Translation- show the RNA strand attatching to a DNA strand with the complimentary base pairs. introns are spliced
2) mRNA leaves the cell and joins with a ribosome
3) Transcription - tRNA (clover shaped) reads each codon (triplets) which each code for an amino acid. The stop codons on the end tell the tRNA that the chain is finished
4) the sequence forms the primary structure (all peptide bonds) which determines the shape of the secondary (hyrdogen and peptide) and hence determines the shape of the tertiary structure of a protein (ionic, hydrogen, disulfide bridges and hydrophibic interactions)
Hope this helps :)
Answer:
option A
an increase in entropy and a decrease in enthalpy
pls mark brainliest
It will lose them and become stable
Answer:
Moles of silver iodide produced = 1.4 mol
Explanation:
Given data:
Mass of calcium iodide = 205 g
Moles of silver iodide produced = ?
Solution:
Chemical equation:
CaI₂ + 2AgNO₃ → 2AgI + Ca(NO₃)₂
Number of moles calcium iodide:
Number of moles = mass/ molar mass
Number of moles = 205 g/ 293.887 g/mol
Number of moles = 0.7 mol
Now we will compare the moles of calcium iodide with silver iodide.
CaI₂ : AgI
1 : 2
0.7 : 2×0.7 = 1.4
Thus 1.4 moles of silver iodide will be formed from 205 g of calcium iodide.
