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gizmo_the_mogwai [7]
3 years ago
11

2. Classify the following solutions as acidic, basic, or neutral at 25OC.

Chemistry
1 answer:
PilotLPTM [1.2K]3 years ago
3 0

Answer: a) pH = 13.00 : basic

b) [H_3O^+]=1.0\times 10^{-12}: basic

c) pOH = 5.00 : basic

d) [OH^-]=1.0\times 10^{-9}: acidic

Explanation:

pH or pOH is the measure of acidity or alkalinity of a solution.

pH is calculated by taking negative logarithm of hydrogen ion concentration.

pH=-\log [H_3O^+]

Acids have pH ranging from 1 to 6.9 and bases have pH ranging from 7.1 to 14.Neutral substances have pH of 7.

a) pH = 13.00

As pH is more than 7, the solution is basic.

b)  [H_3O^+]=1.0\times 10^{-12}

Putting in the values:

pH=-\log[1.0\times 10^{-12}]

pH=12

As pH is more than 7, the solution is basic.

c) pOH = 5.00

pH+pOH=14.0

pH=14.0-5.00=9.00

As pH is more than 7, the solution is basic.

d) [OH^-]=1.0\times 10^{-9}

Putting in the values:

pOH=-\log[1.0\times 10^{-9}]

pOH=9.00

pH+pOH=14.0

pH=14.0-9.00=5.00

As pH is less than 7, the solution is acidic.

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Answer:

The true statement is:

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Explanation:

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  • V_1=49.8mL
  • T_1=18°C=291K
  • T_2=83°C=356K

Using Charles law

\\ \sf\longmapsto V_1T_2=V_2T_1

\\ \sf\longmapsto V_2=V_1T_2\div T_1

\\ \sf\longmapsto V_2=\dfrac{49.8(356)}{291}

\\ \sf\longmapsto V_2=\dfrac{17728.8}{291}

\\ \sf\longmapsto V_2=60.9mL

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The average dosage of oxcarbazepine for an epileptic child between the ages of 4 and 16 is 9.00 mg per 1 kg of body weight (9.00
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Convert the child weight (37.3 pounds) to kilograms

37.3 lb x 0.453 kg /1lb = "A kg"

multiply the dose (9.00mg/kg) by the weight of the child to find how much you need to give him

A kg * 9.00 mg/1kg = "B mg" 

calculate the mL of suspension dividing the "B mg" by the concentration of the suspension 60.0 mg/mL

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For a different reaction, the plot of the reciprocal of concentration versus time in seconds was linear with a slope of 0.056 M-
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Answer:

C_t=0.165M

Explanation:

From the question we are told that:

Slope K=0.056 M-1 s -1

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Time t=100

Generally the equation for Raw law is mathematically given by

\frac{1}{C}_t=kt+\frac{1}{C}_0

\frac{1}{C}_t=0.056*100+\frac{1}{2.2}_0

C_t=0.165M

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3 years ago
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