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3 years ago

7

Write and solve an inequality to find the values of x for which the perimeter of the rectangle is less

1 answer:

avanturin [10]3 years ago

7 0

Answer:

B (if that sign is x + 4)

C (if that sign is x ÷ 4)

Step-by-step explanation:

We know that x is definitely less than the other value, and cannot possibly be equal to the other value, as it's x + 4, so the answer is B.

It's the other way round if it's x ÷ 4 and the answer will be C.

hopefully I interpreted this question the right way!

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I need help please! I've been stuck on this for a week and its really stressful lol

worty [1.4K]

Answer:

$y=0.2*4^{x}$

Step-by-step explanation:

Notice when x increases 1, y is 4 times the previous one, so

the function is like $y=C*4^{x}$

To determine the constant C, put any pair of (x, y)

Use x = 0, y = 0.2, so

0.2 = $C*4^{0}$ = C * 1 = C

then $y=0.2*4^{x}$

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2 years ago

Read 2 more answers

Can someone please help

Rashid [163]

Answer:

It shifted 6 units down

Step-by-step explanation:

Do the graph normally without the k and compare them side by side.

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2 years ago

A cylindrical barrel with a radius of 12 feet rests on its round side against a wall. A ladder leans against both the barrel and

frosja888 [35]

The answer is 24 cool

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3 years ago

Please answer (-4) + (-5)

sertanlavr [38]

-9

There are the same signs so you'd just add them together and use whatever sign they are..

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3 years ago

The difference between the two roots of the equation 3x^2+10x+c=0 is 4 2/3 . Find the solutions for the equation.

andrezito [222]

Answer:

Given the equation: $3x^2+10x+c =0$

A quadratic equation is in the form: $ax^2+bx+c = 0$ where a, b ,c are the coefficient and a≠0 then the solution is given by :

$x_{1,2} = \frac{-b\pm \sqrt{b^2-4ac}}{2a}$ ......[1]

On comparing with given equation we get;

a =3 , b = 10

then, substitute these in equation [1] to solve for c;

$x_{1,2} = \frac{-10\pm \sqrt{10^2-4\cdot 3 \cdot c}}{2 \cdot 3}$

Simplify:

$x_{1,2} = \frac{-10\pm \sqrt{100- 12c}}{6}$

Also, it is given that the difference of two roots of the given equation is $4\frac{2}{3} = \frac{14}{3}$

i.e,

$x_1 -x_2 = \frac{14}{3}$

Here,

$x_1 = \frac{-10 + \sqrt{100- 12c}}{6}$ , ......[2]

$x_2= \frac{-10 - \sqrt{100- 12c}}{6}$ .....[3]

then;

$\frac{-10 + \sqrt{100- 12c}}{6} - (\frac{-10 + \sqrt{100- 12c}}{6}) = \frac{14}{3}$

simplify:

$\frac{2 \sqrt{100- 12c} }{6} = \frac{14}{3}$

or

$\sqrt{100- 12c} = 14$

Squaring both sides we get;

$100-12c = 196$

Subtract 100 from both sides, we get

$100-12c -100= 196-100$

Simplify:

-12c = -96

Divide both sides by -12 we get;

c = 8

Substitute the value of c in equation [2] and [3]; to solve $x_1 , x_2$

$x_1 = \frac{-10 + \sqrt{100- 12\cdot 8}}{6}$

or

$x_1 = \frac{-10 + \sqrt{100- 96}}{6}$ or

$x_1 = \frac{-10 + \sqrt{4}}{6}$

Simplify:

$x_1 = \frac{-4}{3}$

Now, to solve for $x_2$ ;

$x_2 = \frac{-10 - \sqrt{100- 12\cdot 8}}{6}$

or

$x_2 = \frac{-10 - \sqrt{100- 96}}{6}$ or

$x_2 = \frac{-10 - \sqrt{4}}{6}$

Simplify:

$x_2 = -2$

therefore, the solution for the given equation is: $-\frac{4}{3}$ and -2.

3 0

3 years ago