Cobalt has an atomic number (Z) of 27, which means the nuclei of all its isotopes have 27 protons. Cobalt 60 has an atomic mass of 60, so it has 60-27 = 33 neutrons.
The mass of 27 isolated protons plus the mass of 33 isolated neutrons would be:
27*(1.007825 u) + 33*(1.008665 u) = 60.497220 u
The actual mass of the nucleus of 60-Co is 59.933820 u.
Mass defect: 60.497220 u - 59.933820 u = 0.563400 u
The mass defect is equal to the binding energy of a nucleus.
using the fact that 1 u = 931.5 MeV/c^2
(0.563400 u)*(931.5 MeV/u) = 524.807 MeV
Answer:
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Answer:
c
Step-by-step explanation:
First off, we know that (g ° f)(2) is just both functions done in a ordered fashion. In this case, f(x) is done first.
To figure out what f(2) is, all we have to do is find where x = 2 is on the graph. In this case it is on point (2, 3). The input is the x and the output is the y, so f(2) = 3.
Then, we can figure out what g(3) by locating x = 3 on line g. It shows the point (3, 0). This means that g(3) = 0.
5 is 33 because the question ends up being 14+3+16
Answer:
137.51
Step-by-step explanation:
