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insens350 [35]
3 years ago
11

Which compound is soluble in water?(1) PbS (3) Na2S(2) BaS (4) Fe2S3

Chemistry
1 answer:
Anuta_ua [19.1K]3 years ago
6 0
Correct Answer: Na2S

Reason: 
The compound sodium sulfide i.e. Na2S is soluble in water. This compound gives strong alkaline aqueous solutions. On the other hand, the remaining three compounds i.e PbS, BaS and Fe2S3 are non-soluble in water. Often these compounds are also referred as sparingly soluble compounds. 
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Carbon dioxide gas is produced by the reaction of oxygen gas and solid carbon . Write a balanced chemical equation for this reac
grandymaker [24]

I think it’s like this.

C+2O→CO2

5 0
3 years ago
How many protons, neutrons, and electrons are in Uranium-232? How many protons, neutrons, and electrons are in Uranium-232?
QveST [7]

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7 0
3 years ago
Which option is an element <br> A: carbon dioxide <br> B: Water <br> C: Air<br> D: Carbon
Ivenika [448]

Answer:

D: Carbon

Explanation:

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Carbon is also by itself, just C.

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Air is just a mixture of different gas molecules, so therefore it is not an element.  

3 0
3 years ago
Read 2 more answers
Which of the following correctly describes the state of matter of one of the samples? D is a liquid because it retains its shape
Brut [27]
D is a solid because it retains its shape
7 0
3 years ago
a titration of 25.0mL of an x M hcl solution with 0.15M NaOH starts at a burette reading for NaOH of 0.20mL . Thr burette readin
VARVARA [1.3K]
Burette is a very accurate measuring instrument when adding solutions and has a measurement error of 0.05 mL. 
Small volumes of solutions can be transferred from the burette at a controllable rate. 
In this instance NaOH is in the burette.
Initial reading of NaOH is 0.20 mL 
end point is the point at which the chemical reaction reaches completion. In acid base reactions, end point is when all the H⁺ ions have reacted with OH⁻ ions. 
final reading of NaOH is 24.10 mL
to find the volume of NaOH dispensed we have to find the difference between final reading and initial reading 
volume of NaOH added = 24.10 mL - 0.20 mL = 23.90 mL
volume of NaOH dispensed is 23.90 mL
6 0
3 years ago
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