Answer:
ii. < iv. < i. < iii.
Explanation:
Hello,
At first, the entropy is lower in solid-phase systems since their particles are molecularly closer. Next, by knowing that the higher the temperature, the higher the entropy, the gaseous HCl at 25 ºC occupies the second place. After that, it is clear 2 moles of HCl have more entropy than just 1 since the larger the amount of mater the higher the entropy.
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Answer:
See explanation below
Explanation:
In this case, HCl is a strong acid, therefore, it dissociates completely in solution.
To know the quantity of water we need to add, we first need to know the concentration of the acid with pH = 6:
[H⁺] = antlog(-pH)
[H⁺] = antlog(-6) = 1x10⁻⁶ M
This means that the concentration is being diluted.
Now, even if we add great quantities of water, and the concentration and volume change, there is one time that do not change despite the quantity of water added; this is the moles. So, all we have to do, is calculate the moles of the acid in the 1 mL of water, and then, the volume of the acid when it's dilluted:
moles HCl = 0.1 * (1/1000) = 1x10⁻⁴ moles
Now that we have the moles, we can calculate the volume which the acid with the lowest concentration has:
V = mol/M
V = 1x10⁻⁴ / 1x10⁻⁶
V = 100 L
This means that we need to add 99.999 mL of water
Answer:
P₂ = 220.56KPa
Explanation:
Boyles Law P ∝ 1/V => Inverse relationship => Decreasing Volume => Increasing Pressure.
P₁ = 198 KPa P₂ = ?
V₁ = 15.35 Liters V₂ = 13.78 Liters
P₁V₁ = P₂V₂ => P₂ = P₁(V₁/V₂) = 198KPa(15.35 L/ 13.78L) = 220.6KPa
Answer:
Because it goes through the process of sublimation.
Explanation:
