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dangina [55]
2 years ago
8

For your senior project, you would like to build a cyclotron that will accelerate protons to 10% of the speed of light. The larg

est vacuum chamber you can find is 54 cm in diameter. What magnetic field strength will you need?
Physics
1 answer:
viva [34]2 years ago
6 0

Answer:

The magnetic field is 1.16 T.  

Explanation:

speed, v = 10% of speed of light = 3 x 10^7 m/s

diameter, d = 54 cm

radius, r = 0.27 m

charge, q = 1.6 x 10^-19 C

mass, m = 1.67 x 10^-27 kg

Let the magnetic field is B.

The centripetal force is balanced by the magnetic force.  

qvB=\frac{mv^2}{r}\\\\B =\frac{mv}{qr}\\\\B =\frac{1.67\times 10^{-27}\times 3\times 10^{7}}{1.6\times 10^{-19}\times 0.27}\\\\B =1.16 T

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\frac{1}{R_{T}} =  \frac{1}{R_{1}}+\frac{1}{R_{2}}+\frac{1}{R_{3}}... +\frac{1}{R_{n}}

After adding them, you will get the reciprocal again and then compute for the value. The problem says that there are 4 resistors in the circuit that have a resistance of 75.

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Answer:

    wo = 18.75 rev / s

Explanation:

This is an exercise in endowment kinematics, it indicates that the final angular velocity is w_f = 109 rad / s, the time to reach this velocity is t = 1.87 s and the deceleration a = 4.7 rad / s²

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let's reduce to revolutions / s

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         w₀ = 18.75 rev / s

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Does that make sense?
</span></span>
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