Answer:
Total magnification is the amount of magnification that can be achieved when all the optics involved in the magnification by the apparatus being used is taken into account.
Explanation:
Total magnification is the amount of magnification that can be achieved when all the optics involved in the magnification by the apparatus being used is taken into account. For example when an object is viewed under a microscope with just ocular and objective lenses, the object is magnified to it maximum magnification using both the ocular lens and objective lens and the total magnification can be calculated by multiplying the power of the objective lens and the power of the eye piece.
Total magnification = power of objective lens x power of eyepiece
Voltage = current * resistance
Voltage = 12 * 4
Voltage = 48V
Answer:
(a) 0.345 T
(b) 0.389 T
Solution:
As per the question:
Hall emf, 
Magnetic Field, B = 0.10 T
Hall emf, 
Now,
Drift velocity, 
Now, the expression for the electric field is given by:
(1)
And
Thus eqn (1) becomes
where
d = distance
(2)
(a) When 
(b) When 
Infrared radiation<span> lies between the </span>visible<span> and microwave portions of the electromagnetic spectrum. Infrared waves have wavelengths longer </span>than visible<span> and shorter </span>than<span> microwaves, and have </span>frequencies<span> which are lower </span>than visible<span> and </span>higher than<span> microwaves.</span>
Answer:
21.35 cm^3
Explanation:
let the volume at the surface of fresh water is V.
The volume at a depth of 100 m is V' = 2 cm^3
temperature remains constant.
density of water, d = 1000 kg/m^3
Pressure at the surface of fresh water is atmospheric pressure,
P = Po = 1.013 x 10^5 N/m^2
The pressure at depth 100 m is P' = Po + hdg
P' = 
P' = 10.813 x 10^5 N/m^2
Use the Boyle's law
P V = P' V'
V = 21.35 cm^3
Thus, the volume of air bubble at the surface of fresh water is 21.35 cm^3.
